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Aditi B.

Mansarovar, Jaipur, India - 302020

Aditi B. Class I-V Tuition trainer in Jaipur

Aditi B.

Educator in Mathematics with more than 5 years of experience...

Mansarovar, Jaipur, India - 302020.

5.0

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Education

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Overview

I am a Manager, Researcher and Educator with more than 5 years of experience in curriculum design and learner-centric instruction. My experience ranges from teaching Mathematics to students from diverse age groups to application of different approaches to provide effective learning solutions. I have also worked on curriculum development at institutions like Adani Foundation among others and have also conducted training programmes for teachers at teacher training institutes.

As an UrbanPro Online Mathematics Tutor, I am interested in helping students to achieve their full academic potential that could also contribute to their future career goals. In my online tuitions, I also address the problems of students in Mathematics by emphasising on the Mathematical principles and on the simpler approaches to solve a particular problem.

Mathematics is one of the most important subjects these days in context of increasing technological development globally. I believe that students differ in their learning styles. Hence, understanding the preferred learning mode of students serves as the basis for providing effective student-oriented learning solutions.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Education

University of Sheffield 2018

Master of Arts (M.A.)

Address

Mansarovar, Jaipur, India - 302020

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Class I-V Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

7

Board

ICSE, International Baccalaureate, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

I am a Manager, Researcher and Educator with more than 5 years of experience in curriculum design and learner-centric instruction. My experience ranges from teaching Mathematics to students from diverse age groups to application of different approaches to provide effective learning solutions. I have worked on curriculum development at institutions like Adani Foundation and have also conducted training programmes for teachers at teacher training institutes. As an UrbanPro Online Mathematics Tutor, I am interested in helping students to achieve their full academic potential that could also contribute to their fututre career goals. Mathematics is one of the most important subjects these days in context of increasing technological development globally. I believe that students differ in their learning styles. Hence, understanding the preferred learning mode of students serves as the basis for providing effective student-oriented learning solutions. In my online tuitions, I also address the problems of students in Mathematics by emphasising on the Mathematical principles and on the simpler approaches to solve a particular problem.

Taught in School or College

Yes

Documents (1)

Curriculum development - Adani...

Reviews

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FAQs

1. Which school boards of Class 1-5 do you teach for?

ICSE, International Baccalaureate and CBSE

2. Have you ever taught in any School or College?

Yes

3. Which classes do you teach?

I teach Class I-V Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 7 years.

Answers by Aditi B. (1)

Answered on 22/06/2019 Tuition

Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution... ...more

Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution of given values, the answer would be 3xyz. 

Answers 278 Comments
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Class I-V Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class I-V Tuition

7

Board

ICSE, International Baccalaureate, CBSE

IB Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Experience in School or College

I am a Manager, Researcher and Educator with more than 5 years of experience in curriculum design and learner-centric instruction. My experience ranges from teaching Mathematics to students from diverse age groups to application of different approaches to provide effective learning solutions. I have worked on curriculum development at institutions like Adani Foundation and have also conducted training programmes for teachers at teacher training institutes. As an UrbanPro Online Mathematics Tutor, I am interested in helping students to achieve their full academic potential that could also contribute to their fututre career goals. Mathematics is one of the most important subjects these days in context of increasing technological development globally. I believe that students differ in their learning styles. Hence, understanding the preferred learning mode of students serves as the basis for providing effective student-oriented learning solutions. In my online tuitions, I also address the problems of students in Mathematics by emphasising on the Mathematical principles and on the simpler approaches to solve a particular problem.

Taught in School or College

Yes

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No Reviews yet! Be the first one to Review

Answers by Aditi B. (1)

Answered on 22/06/2019 Tuition

Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution... ...more

Answer would be 3xyz. The solution to this question requires the use of equation and substitution of given values. The equation that is applicable here is: x^3 + y^3 + z^3 -3xyz = (x+y+z) (x^2 + y^2 + z^2 - xy - yz - zx). Since the product on the right hand side of equation is zero after substitution of given values, the answer would be 3xyz. 

Answers 278 Comments
Dislike Bookmark

Aditi B. describes herself as Educator in Mathematics with more than 5 years of experience in teaching and course design. She conducts classes in Class I-V Tuition. Aditi is located in Mansarovar, Jaipur. Aditi takes Online Classes- via online medium. She has 7 years of teaching experience . Aditi has completed Master of Arts (M.A.) from University of Sheffield in 2018. She is well versed in English and Hindi.

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