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Buddhadeb Chandra BSc Tuition trainer in Noida

Buddhadeb Chandra

Tutor, The ultimate solution to the fear of Organic Chemistry, PhD from DRDO in Chemical Science.

Sector 119, Noida, India - 201307.

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Referral Discount: Get ₹ 500 off when you make a payment to start classes. Get started by Booking a Demo.

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Overview

I am a qualified and experienced teacher and tutor with over 3 years experience in teaching Chemistry of CBSE and State Board level. Passionate to clear the basic concept of the students in chemistry especially to overcome the fear about different chemical reaction of Organic Chemistry. Now I am continuing my PhD in Chemical Science from DRDE, Gwalior.

Languages Spoken

Bengali Mother Tongue (Native)

English Proficient

Hindi Proficient

Education

Nagpur University 2014

Master of Science (M.Sc.)

Address

Sector 119, Noida, India - 201307

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Teaches

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

3

BSc Chemistry Subjects

Concepts In Inorganic Chemistry, Polymer Chemistry, Organic Qualitative & Quantitative Analysis, Hydrocarbons And Stereochemistry, Organic Functional Groups, Spectroscopy

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Chemistry

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Teaching Experience in detail in Class 12 Tuition

I have 5 years teaching experience on all branch of chemistry like physical, organic and inorganic chemistry. During taking classes I observed that students were fear about solving mathematical problem, especially in physical chemistry. Here my responsibility was to provide proper technique how they can easily understand the problem and save themselves from the fear of solving mathematical problems. Another students fears were on different types of organic reaction and their mechanism. In this case at first I clear their basic concept about reaction and how the reaction proceeds following particular pathway. During my B.Sc. I provide chemistry tuition for three years, state board level in West Bengal. During my M.Sc. from Nagpur university I provide chemistry tuition for two years, CBSE level. Now I pursuing my PhD from DRDE, Gwalior and looking some class 11 & 12 level students for providing sound chemistry tuition.

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Teaching Experience in detail in Class 11 Tuition

The interesting experience about my class 11 Tuition was my first class on structure of atom. Here starting from Dalton's atomic theory via Bohr's atomic model to quantum mechanical model of atom. Most of the students are confused about all these things and started fearing the chapter. But I try to explain this chapter in front of the students just like a story. So that they can easily grab the whole matter. Another chapter is Chemical Thermodynamics, there are limitless fear in the students mind about this chapter. This problem was being solved with the help of diagramtical explanation and provide different techniques how to remember the related terminology.

Reviews

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FAQs

1. Do you have any prior teaching experience?

No

2. Which classes do you teach?

I teach BSc Tuition, Class 11 Tuition and Class 12 Tuition Classes.

3. Do you provide a demo class?

No, I don't provide a demo class.

4. How many years of experience do you have?

I have been teaching for 3 years.

Answers by Buddhadeb Chandra (10)

Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions +1 CBSE/Class 11/Science/Chemistry

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18... ...more

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

Answers 20 Comments
Dislike Bookmark

Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions +1 CBSE/Class 11/Science/Chemistry

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18... ...more

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

Answers 20 Comments
Dislike Bookmark

Answered on 17/03/2019 Learn Tuition Fee

Rs 3500 - 4000/- for 12 days in a month or Rs 300/hr.
Answers 41 Comments
Dislike Bookmark

Teaches

BSc Tuition

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

3

BSc Chemistry Subjects

Concepts In Inorganic Chemistry, Polymer Chemistry, Organic Qualitative & Quantitative Analysis, Hydrocarbons And Stereochemistry, Organic Functional Groups, Spectroscopy

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Chemistry

Class 12 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

5

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Teaching Experience in detail in Class 12 Tuition

I have 5 years teaching experience on all branch of chemistry like physical, organic and inorganic chemistry. During taking classes I observed that students were fear about solving mathematical problem, especially in physical chemistry. Here my responsibility was to provide proper technique how they can easily understand the problem and save themselves from the fear of solving mathematical problems. Another students fears were on different types of organic reaction and their mechanism. In this case at first I clear their basic concept about reaction and how the reaction proceeds following particular pathway. During my B.Sc. I provide chemistry tuition for three years, state board level in West Bengal. During my M.Sc. from Nagpur university I provide chemistry tuition for two years, CBSE level. Now I pursuing my PhD from DRDE, Gwalior and looking some class 11 & 12 level students for providing sound chemistry tuition.

Class 11 Tuition
1 Student

Class Location

Online (video chat via skype, google hangout etc)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

5

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Teaching Experience in detail in Class 11 Tuition

The interesting experience about my class 11 Tuition was my first class on structure of atom. Here starting from Dalton's atomic theory via Bohr's atomic model to quantum mechanical model of atom. Most of the students are confused about all these things and started fearing the chapter. But I try to explain this chapter in front of the students just like a story. So that they can easily grab the whole matter. Another chapter is Chemical Thermodynamics, there are limitless fear in the students mind about this chapter. This problem was being solved with the help of diagramtical explanation and provide different techniques how to remember the related terminology.

No Reviews yet! Be the first one to Review

Answers by Buddhadeb Chandra (10)

Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions +1 CBSE/Class 11/Science/Chemistry

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18... ...more

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

Answers 20 Comments
Dislike Bookmark

Answered on 17/03/2019 Learn CBSE/Class 11/Science/Chemistry/Redox Reactions +1 CBSE/Class 11/Science/Chemistry

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula x + nL + Nvse = 18... ...more

Oxidation state of central atom of metal complexs calculateted on the basis of '18 electron rule' viz. after complex formation each central metal contain total no. of 18 valance electrons. For calculation of oxidation state of central metal atom we can follow the following formula

x + nL + Nvse = 18 ( here x = oxidation state of central metal atom, n = total no of like ligand, L = electron contribution, Nvse = no of valence shell electron of the central atom only)

For given problem: x + 4 x 2 + 10 = 18 or x = 0; hence oxidation state of Ni in Ni(CO)4 is 0.

Answers 20 Comments
Dislike Bookmark

Answered on 17/03/2019 Learn Tuition Fee

Rs 3500 - 4000/- for 12 days in a month or Rs 300/hr.
Answers 41 Comments
Dislike Bookmark

Contact

Load More

Buddhadeb Chandra describes himself as Tutor, The ultimate solution to the fear of Organic Chemistry, PhD from DRDO in Chemical Science.. He conducts classes in BSc Tuition, Class 11 Tuition and Class 12 Tuition. Buddhadeb is located in Sector 119, Noida. Buddhadeb takes at students Home. He has 5 years of teaching experience . Buddhadeb has completed Master of Science (M.Sc.) from Nagpur University in 2014. He is well versed in English, Bengali and Hindi.

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