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BSc Tuition > BSc Tuition in Gurgaon > BSc Tuition in Sector 23 > Bindia H.

Bindia H. BSc Tuition trainer in Gurgaon

Bindia H.

locationImg Sector 23, Gurgaon
2 yrs of Exp
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Details verified of Bindia H.✕

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Education

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Electronics & Communications Expert

Online Classes
Student's home
Tutor's home
Core Subjects: Digital Signal Processing, Wireless Communications, Electrical Circuit Analysis, Electronic Devices, VLSI

Application Software: MATLAB, Optisystem, Orcad 16.0, Xilinx ISE

Scripting Languages: Unix Shell Scripting, Perl Scripting Programming Languages: Verilog, C, Visual C++, Visual Basic, PL/SQL

WireLine INSITE Quad for HALLIBURTON
â?ª Developed/ Enhanced tools & applications using MFC, Visual C++ as front end & Ms-Access as back end.
â?ª Worked on InSite Core, Plotting & assisted in the maintenance of Data Logs.

File Transfer System for RLL
â?ª Developed console based User Interface to allow two remote machines to transfer files between them using C Language.
â?ª Maintained Login & File Transfer Logs.

National Science Olympiad subject topper for Chemistry.

Languages Spoken

Punjabi Proficient

English Proficient

Hindi Proficient

Education

Guru Nanak Dev University, Amritsar Pursuing

Master of Engineering - Master of Technology (M.E./M.Tech.)

Address

Sector 23, Gurgaon, India - 122001

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Teaches

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

2

BSc Electronics Subjects

Signals and Systems, Digital Communication, Analog Communication, Fundamental of Programming Languages, Network Analysis, Mathematics, Digital Electronics, Data Structures, Analog Electronics, Semiconductor Devices

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

BSc Branch

BSc Electronics

BTech Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Electrical & Electronics subjects

Analog And Digital Communication, Electrical Circuit Analysis

BTech Electrical & Communication

Semiconductor Device Physics, Digital Communication, Communication Networks, Wireless Communication, Information Theory and Coding, Satellite Communication, Digital Image Processing, Optical Fiber Communication, (VLSI/ULSI) Very Large Scale Integration Process Technology, Digital Electronics, Electronic Circuit Design, Mobile Communication, Data Structures and Algorithms, Analog Communication, Analog Electronics, Object Oriented Programming

BTech Branch

BTech Electrical & Communication Engineering

BTech Instrumentation subjects

Digital Signal Processing

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

MATLAB Training

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in MATLAB Training

2

Reviews

No Reviews yet!

Answers by Bindia H.

Answered on 25/06/2019

Ask a Question

Post a Lesson

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

Given: x² +y² +z² = xy + yz + zx This can be re-written as: x² +y² +z² - xy - yz - zx = 0 Multiplying both sides by (x + y + z) : (x + y + z) (x² +y² +z² - xy – yz – zx) = 0 Simplifying: x³ + xy² + xz² - x²y - xyz -zx²... ...more

Given:  x² +y² +z² =  xy + yz + zx

This can be re-written as: x² +y² +z² -  xy - yz - zx = 0

Multiplying both sides by (x + y + z) :  (x + y + z) (x² +y² +z² -  xy – yz – zx) = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + y³ + z³ - 3xyz = 0 or  x³ + y³ + z³ = 3xyz

Answers 278 Comments
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Teaches

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

2

BSc Electronics Subjects

Signals and Systems, Digital Communication, Analog Communication, Fundamental of Programming Languages, Network Analysis, Mathematics, Digital Electronics, Data Structures, Analog Electronics, Semiconductor Devices

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

BSc Branch

BSc Electronics

BTech Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in BTech Tuition

2

BTech Electrical & Electronics subjects

Analog And Digital Communication, Electrical Circuit Analysis

BTech Electrical & Communication

Semiconductor Device Physics, Digital Communication, Communication Networks, Wireless Communication, Information Theory and Coding, Satellite Communication, Digital Image Processing, Optical Fiber Communication, (VLSI/ULSI) Very Large Scale Integration Process Technology, Digital Electronics, Electronic Circuit Design, Mobile Communication, Data Structures and Algorithms, Analog Communication, Analog Electronics, Object Oriented Programming

BTech Branch

BTech Electrical & Communication Engineering

BTech Instrumentation subjects

Digital Signal Processing

Type of class

Regular Classes

Class strength catered to

Group Classes

Taught in School or College

No

MATLAB Training

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in MATLAB Training

2

No Reviews yet!

Answers by Bindia H.

Answered on 25/06/2019

Ask a Question

Post a Lesson

<p>if x^2+y^2+z^2=xy+yz+zx then find the value of x^3+y^3+z^3</p>

Given: x² +y² +z² = xy + yz + zx This can be re-written as: x² +y² +z² - xy - yz - zx = 0 Multiplying both sides by (x + y + z) : (x + y + z) (x² +y² +z² - xy – yz – zx) = 0 Simplifying: x³ + xy² + xz² - x²y - xyz -zx²... ...more

Given:  x² +y² +z² =  xy + yz + zx

This can be re-written as: x² +y² +z² -  xy - yz - zx = 0

Multiplying both sides by (x + y + z) :  (x + y + z) (x² +y² +z² -  xy – yz – zx) = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + xy² + xz² - x²y - xyz -zx² + yx² + y³ + yz² - xy² - y²z - xyz + zx² + zy² + z³ - xyz - yz² - z²x = 0

Simplifying: x³ + y³ + z³ - 3xyz = 0 or  x³ + y³ + z³ = 3xyz

Answers 278 Comments
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