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Vaishali Class 12 Tuition trainer in Delhi

Vaishali

locationImg Palam Colony, Delhi
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Hello, my name is Vaishali currently i am pursuing my MSc chemistry degree from central university of haryana and i have completed my Bachelor's in Science from University of Delhi in 2019. I have also qualified the CSIR UGC NET exam in 2020 With AIR 70. I also have a experience in teaching class 6 to 10 in science and class 11th to 12th in chemistry. I love to convey my knowledge to coming generation so that they can learn and do much better in future, i give my all, to teach students and also learn from them.

Languages Spoken

English

Hindi

Education

University of delhi 2019

BSc (Hons) Chemistry

Central University of Haryana 2021

MSc in Chemistry

NTA 2020

CSIR UGC NET (LS)

Address

Palam Colony, Delhi, India - 110045

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Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Chemistry

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

Subjects taught

Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

English, Science, EVS

Taught in School or College

No

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BSc Chemistry Subjects

Inorganic Qualitative & Quantitative Analysis, Transition Elements And Nuclear Chemistry, Electrochemistry, Phase Equilibria And Kinetics, Spectroscopy, Organic Qualitative & Quantitative Analysis, Polymer Chemistry, Thermodynamics, Chemistry For Biologists, Organic Functional Groups, Concepts In Inorganic Chemistry, Hydrocarbons And Stereochemistry, Main Group Elements And Solid State Chemistry, Coordination Chemistry

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Chemistry

Reviews

No Reviews yet!

Answers by Vaishali

Answered on 30/08/2021 Learn IIT JEE/IIT - JEE Mains/Chemistry/Organic Chemistry/Chemistry in Everyday Life +2 CBSE - Class 11/Chemistry CBSE - Class 11/Chemistry/Organic Chemistry – Some Basic Principles and Techniques

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Post a Lesson

Kernal is a term used for metal ions produced due to the delocalization of the electron in the crystal lattice.
Answers 32 Comments
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Answered on 19/04/2018

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2000 rupees per month
Answers 1475 Comments
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Answered on 07/04/2018 Learn CBSE - Class 10/Mathematics +2 Profit, Loss and Discount

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Here , cost price (C. P) = 1400 Loss %=15 So, the total loss =15% of 1400 =15/100 * 1400 =15*14 = Rs 210 Now we will get selling price by subtracting the loss from the price at which he buyed. So, S.P = 1400-210 = Rs1190 ...more

Here , cost price (C. P) = 1400 

Loss %=15

So, the total loss =15% of 1400

                               =15/100 * 1400 =15*14 = Rs 210

Now we will get  selling price by subtracting the loss from the price at which he buyed. 

So,  S.P = 1400-210 =   Rs1190

Answers 39 Comments
Dislike Bookmark

Answered on 01/01/2018 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

A pure substance is one that constitutes of the same types of particles. For eg : 24 carrat gold is pure as it has no other metal present in it butthe gold in its pure form is semi solid and in this case it can be easily broken in pieces with hand. So to make gold harder and tougher it is made an alloy... ...more
A pure substance is one that constitutes of the same types of particles. For eg : 24 carrat gold is pure as it has no other metal present in it butthe gold in its pure form is semi solid and in this case it can be easily broken in pieces with hand. So to make gold harder and tougher it is made an alloy by adding other metals to it which give it rigidity.
Answers 7 Comments
Dislike Bookmark

Answered on 01/01/2018 Learn CBSE - Class 9/Science +1

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Post a Lesson

20Hz to 20000Hz is the audible range of frequency for human beings
Answers 7 Comments
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Please enter your Question

Please select a Tag

Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Board

CBSE

Subjects taught

Chemistry

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE

Subjects taught

Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 9 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 10 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

2

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 6 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 6 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

Yes

Class 7 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 7 Tuition

1

Board

CBSE

Subjects taught

Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 8 Tuition

2

Board

CBSE

Subjects taught

English, Science, EVS

Taught in School or College

No

BSc Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

BSc Chemistry Subjects

Inorganic Qualitative & Quantitative Analysis, Transition Elements And Nuclear Chemistry, Electrochemistry, Phase Equilibria And Kinetics, Spectroscopy, Organic Qualitative & Quantitative Analysis, Polymer Chemistry, Thermodynamics, Chemistry For Biologists, Organic Functional Groups, Concepts In Inorganic Chemistry, Hydrocarbons And Stereochemistry, Main Group Elements And Solid State Chemistry, Coordination Chemistry

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions, Group Classes

Taught in School or College

No

BSc Branch

BSc Chemistry

No Reviews yet!

Answers by Vaishali

Answered on 30/08/2021 Learn IIT JEE/IIT - JEE Mains/Chemistry/Organic Chemistry/Chemistry in Everyday Life +2 CBSE - Class 11/Chemistry CBSE - Class 11/Chemistry/Organic Chemistry – Some Basic Principles and Techniques

Ask a Question

Post a Lesson

Kernal is a term used for metal ions produced due to the delocalization of the electron in the crystal lattice.
Answers 32 Comments
Dislike Bookmark

Answered on 19/04/2018

Ask a Question

Post a Lesson

2000 rupees per month
Answers 1475 Comments
Dislike Bookmark

Answered on 07/04/2018 Learn CBSE - Class 10/Mathematics +2 Profit, Loss and Discount

Ask a Question

Post a Lesson

Here , cost price (C. P) = 1400 Loss %=15 So, the total loss =15% of 1400 =15/100 * 1400 =15*14 = Rs 210 Now we will get selling price by subtracting the loss from the price at which he buyed. So, S.P = 1400-210 = Rs1190 ...more

Here , cost price (C. P) = 1400 

Loss %=15

So, the total loss =15% of 1400

                               =15/100 * 1400 =15*14 = Rs 210

Now we will get  selling price by subtracting the loss from the price at which he buyed. 

So,  S.P = 1400-210 =   Rs1190

Answers 39 Comments
Dislike Bookmark

Answered on 01/01/2018 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

A pure substance is one that constitutes of the same types of particles. For eg : 24 carrat gold is pure as it has no other metal present in it butthe gold in its pure form is semi solid and in this case it can be easily broken in pieces with hand. So to make gold harder and tougher it is made an alloy... ...more
A pure substance is one that constitutes of the same types of particles. For eg : 24 carrat gold is pure as it has no other metal present in it butthe gold in its pure form is semi solid and in this case it can be easily broken in pieces with hand. So to make gold harder and tougher it is made an alloy by adding other metals to it which give it rigidity.
Answers 7 Comments
Dislike Bookmark

Answered on 01/01/2018 Learn CBSE - Class 9/Science +1

Ask a Question

Post a Lesson

20Hz to 20000Hz is the audible range of frequency for human beings
Answers 7 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

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