Jagriti S.

Chattarpur Extension, Delhi, India - 110074

Jagriti S. photo

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Jagriti S.

Tutor

Chattarpur Extension, Delhi, India - 110074.

5.0

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Overview

Currently working with a well known organization which gives coaching classes for JEE mains and advanced as well as NEET.

Languages Spoken

Hindi

English

Education

IIT kharagpur 2018

Master of Science (M.Sc.)

Address

Chattarpur Extension, Delhi, India - 110074

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Class 12 Tuition Overview

Class 12 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

2

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Reviews

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Answers by Jagriti S. (2)

Answered on 08 Feb CBSE/Class 11/Science/Chemistry/Unit 8-Redox Reaction CBSE/Class 11/Science/Chemistry

As CO is a neutral ligand and the coordination sphere also bears a zero charge the O.S of Fe in Fe(CO)5 is zero. let x be the O.S of Fe in the complex, then x+ 5*0=0 x=0
Answers 4 Comments
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Answered on 07 Feb CBSE/Class 11/Science/Chemistry/Unit 11-Some p -Block Elements CBSE/Class 11/Science/Chemistry

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the... ...more

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the case of boron halides typically with chlorides,bromides,iodides boron completes its electron defiency by forming adduct with NH3 also its hybridisation changes from sp2 to sp3 while it does so. taking BF3 as a special case, it involves back bonding (2p-2p) overlap so it is least probable to form adduct with lewis bases such as NH3.

Answers 3 Comments
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Jagriti S.Directions

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Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

2

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

Class 11 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

2

Board

CBSE, State, ISC/ICSE

ISC/ICSE Subjects taught

Chemistry

CBSE Subjects taught

Chemistry

Taught in School or College

No

State Syllabus Subjects taught

Chemistry

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Answers by Jagriti S. (2)

Answered on 08 Feb CBSE/Class 11/Science/Chemistry/Unit 8-Redox Reaction CBSE/Class 11/Science/Chemistry

As CO is a neutral ligand and the coordination sphere also bears a zero charge the O.S of Fe in Fe(CO)5 is zero. let x be the O.S of Fe in the complex, then x+ 5*0=0 x=0
Answers 4 Comments
Dislike Bookmark

Answered on 07 Feb CBSE/Class 11/Science/Chemistry/Unit 11-Some p -Block Elements CBSE/Class 11/Science/Chemistry

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the... ...more

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the case of boron halides typically with chlorides,bromides,iodides boron completes its electron defiency by forming adduct with NH3 also its hybridisation changes from sp2 to sp3 while it does so. taking BF3 as a special case, it involves back bonding (2p-2p) overlap so it is least probable to form adduct with lewis bases such as NH3.

Answers 3 Comments
Dislike Bookmark

Jagriti S. describes herself as Tutor. She conducts classes in Class 11 Tuition and Class 12 Tuition. Jagriti is located in Chattarpur Extension, Delhi. Jagriti takes at students Home, Regular Classes- at her Home and Online Classes- via online medium. She has 2 years of teaching experience . Jagriti has completed Master of Science (M.Sc.) from IIT kharagpur in 2018. She is well versed in Hindi and English.

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