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Jagriti S. Class 12 Tuition trainer in Delhi

Jagriti S.

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experience 2 yrs of Exp
locationImg Chattarpur Extension, Delhi
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Jagriti S. - Tutor

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Currently working with a well known organization which gives coaching classes for JEE mains and advanced as well as NEET.

Languages Spoken

Hindi

English

Education

IIT kharagpur 2018

Master of Science (M.Sc.)

Address

Chattarpur Extension, Delhi, India - 110074

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Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE, State, ISC/ICSE

Subjects taught

Chemistry

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State, ISC/ICSE

Subjects taught

Chemistry

Taught in School or College

No

Reviews

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Answers by Jagriti S.

Answered on 08/02/2019 Learn CBSE - Class 11/Chemistry/Redox Reactions +1 CBSE - Class 11/Chemistry

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As CO is a neutral ligand and the coordination sphere also bears a zero charge the O.S of Fe in Fe(CO)5 is zero. let x be the O.S of Fe in the complex, then x+ 5*0=0 x=0
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Answered on 07/02/2019 Learn CBSE - Class 11/Chemistry/Unit 11-Some p -Block Elements +1 CBSE - Class 11/Chemistry

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Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the... ...more

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the case of boron halides typically with chlorides,bromides,iodides boron completes its electron defiency by forming adduct with NH3 also its hybridisation changes from sp2 to sp3 while it does so. taking BF3 as a special case, it involves back bonding (2p-2p) overlap so it is least probable to form adduct with lewis bases such as NH3.

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Teaches

Class 12 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

2

Board

CBSE, State, ISC/ICSE

Subjects taught

Chemistry

Taught in School or College

No

Class 11 Tuition

Class Location

Online class via Zoom

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

2

Board

CBSE, State, ISC/ICSE

Subjects taught

Chemistry

Taught in School or College

No

No Reviews yet!

Answers by Jagriti S.

Answered on 08/02/2019 Learn CBSE - Class 11/Chemistry/Redox Reactions +1 CBSE - Class 11/Chemistry

Ask a Question Ask a Question

Post a Lesson Post a Lesson

As CO is a neutral ligand and the coordination sphere also bears a zero charge the O.S of Fe in Fe(CO)5 is zero. let x be the O.S of Fe in the complex, then x+ 5*0=0 x=0
Answer Answers 4 Comments Comments
Dislike Bookmark

Answered on 07/02/2019 Learn CBSE - Class 11/Chemistry/Unit 11-Some p -Block Elements +1 CBSE - Class 11/Chemistry

Ask a Question Ask a Question

Post a Lesson Post a Lesson

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the... ...more

Boron and other 13th group elements in the periodic table generally forms electron deficient compounds. Therefore to minimise their electron deficiency either they form adduct with some electron donor species generally lewis bases (such as NH3) or dimerise ( as in the case of B2H6 or Al2Cl6). In the case of boron halides typically with chlorides,bromides,iodides boron completes its electron defiency by forming adduct with NH3 also its hybridisation changes from sp2 to sp3 while it does so. taking BF3 as a special case, it involves back bonding (2p-2p) overlap so it is least probable to form adduct with lewis bases such as NH3.

Answer Answers 3 Comments Comments
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