Pusa, Delhi Details verified of Geeta M.✕
Identity
Education
Know how UrbanPro verifies Tutor details
Identity is verified based on matching the details uploaded by the Tutor with government databases.
Online Classes 
Share this profile Hindi Mother Tongue (Native)
Delhi University 1977
Bachelor of Arts (B.A.)
Yogrish Astro Research Centre 2023
Advance Vedic Astrology
Pusa, Delhi, India - 110012
ID Verified
Education Verified
Phone Verified
Email Verified
Report this Profile
Is this listing inaccurate or duplicate? Any other problem?
Please tell us about the problem and we will fix it.
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Astrology Classes
3
Answered on 26/02/2024 Learn CBSE - Class 8/Maths/Factorization
Ask a Question
Post a Lesson
To factorize the quadratic expression x2+6x+8x2+6x+8, we're looking for two binomials of the form (x+p)(x+q)(x+p)(x+q) where pp and qq are numbers such that:
(x+p)(x+q)=x2+(p+q)x+pq(x+p)(x+q)=x2+(p+q)x+pq
In this case, we want p+qp+q to be equal to the coefficient of xx in the given expression (which is 6) and pqpq to be equal to the constant term (which is 8).
Let's find pp and qq:
p+q=6p+q=6 pq=8pq=8
The pairs of numbers that satisfy these conditions are p=2p=2 and q=4q=4.
Therefore, the factorization is:
x2+6x+8=(x+2)(x+4)x2+6x+8=(x+2)(x+4)
Like 0 
Answers 2 
Comments Ask a Question
Also have a look at
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Astrology Classes
3
Answered on 26/02/2024 Learn CBSE - Class 8/Maths/Factorization
Ask a Question
Post a Lesson
To factorize the quadratic expression x2+6x+8x2+6x+8, we're looking for two binomials of the form (x+p)(x+q)(x+p)(x+q) where pp and qq are numbers such that:
(x+p)(x+q)=x2+(p+q)x+pq(x+p)(x+q)=x2+(p+q)x+pq
In this case, we want p+qp+q to be equal to the coefficient of xx in the given expression (which is 6) and pqpq to be equal to the constant term (which is 8).
Let's find pp and qq:
p+q=6p+q=6 pq=8pq=8
The pairs of numbers that satisfy these conditions are p=2p=2 and q=4q=4.
Therefore, the factorization is:
x2+6x+8=(x+2)(x+4)x2+6x+8=(x+2)(x+4)
Like 0 Answers 2 Comments Ask a Question
Want to learn from Geeta M.?
Share this profile 
Reply to 's review
Enter your reply*
Your reply has been successfully submitted.
Certified
The Certified badge indicates that the Tutor has received good amount of positive feedback from Students.
