Coaching classes for IB, CBSE, IGCSE & ICSE boards.
Classes - 2 to 12
All subjects including Hindi , Computer & Sanskrit.
Katwaria Sarai, Delhi, India - 110016
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F-68 WELL NO 2
KATWARIA SARAI HAUZ KHAS DELHI
Katwaria Sarai, Delhi, India - 110016
Landmark: well no 2
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Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
ISC/ICSE, IGCSE, International Baccalaureate, CBSE
Subjects taught
Geography, Physics, Mathematics, History, Political Science, Economics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
ISC/ICSE, IGCSE, International Baccalaureate, CBSE
Subjects taught
Physics, Political Science, Mathematics, Geography, Sociology, Economics, History, Social science
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Subjects taught
EVS, History and Civics, Physics, Chemistry, Geography, Mathematics, Social Science, Hindi, Economics, Computer Application, Science, History, Economic Application
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Subjects taught
Science, Chemistry, Computer Application, History, Geography, Economic Application, Mathematics, Social Science, English, Economics, History and Civics, EVS, Computers, Physics
Upcoming Live Classes
1. Which school boards of Class 12 do you teach for?
ISC/ICSE, IGCSE, International Baccalaureate and others
2. Which classes do you teach?
We teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class 9 Tuition Classes
3. Do you provide a demo class?
Yes, We provide a free demo class.
4. Where are you located?
We are located in Katwaria Sarai, Delhi.
Answered on 02/10/2018
Answered on 28/09/2018
m = 1000kg
u(initial velocity) = 0 ; as the body starts from rest .
v( final velocity ) = 54 km/h = 15 m/s
t(time) = 5 sec
using equation of motion ,
v = u + at , or
15 = 0 + a*5, or
a = (15-0) / 5
so , a = 3 m /s^2
now , we know kinetic energy = 1/2 M V^2
so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
ISC/ICSE, IGCSE, International Baccalaureate, CBSE
Subjects taught
Geography, Physics, Mathematics, History, Political Science, Economics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
ISC/ICSE, IGCSE, International Baccalaureate, CBSE
Subjects taught
Physics, Political Science, Mathematics, Geography, Sociology, Economics, History, Social science
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Subjects taught
EVS, History and Civics, Physics, Chemistry, Geography, Mathematics, Social Science, Hindi, Economics, Computer Application, Science, History, Economic Application
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Subjects taught
Science, Chemistry, Computer Application, History, Geography, Economic Application, Mathematics, Social Science, English, Economics, History and Civics, EVS, Computers, Physics
Answered on 02/10/2018
Answered on 28/09/2018
m = 1000kg
u(initial velocity) = 0 ; as the body starts from rest .
v( final velocity ) = 54 km/h = 15 m/s
t(time) = 5 sec
using equation of motion ,
v = u + at , or
15 = 0 + a*5, or
a = (15-0) / 5
so , a = 3 m /s^2
now , we know kinetic energy = 1/2 M V^2
so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .
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