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Excellence Class 11 Tuition institute in Delhi

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Coaching classes for IB, CBSE, IGCSE & ICSE boards.
Classes - 2 to 12
All subjects including Hindi , Computer & Sanskrit.

Address

F-68 WELL NO 2

KATWARIA SARAI HAUZ KHAS DELHI

Katwaria Sarai, Delhi, India - 110016

Landmark: well no 2

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Teaches

Class 11 Tuition

Class Location

Online class via Zoom

At the Institute

Board

International Baccalaureate, CBSE, IGCSE, ISC/ICSE

Subjects taught

Physics, Economics, Mathematics, History, Political Science, Geography

Class 12 Tuition

Class Location

Online class via Zoom

At the Institute

Board

International Baccalaureate, CBSE, IGCSE, ISC/ICSE

Subjects taught

Economics, Geography, Physics, Sociology, History, Political Science, Mathematics, Social science

Class 9 Tuition

Class Location

Online class via Zoom

At the Institute

Board

IGCSE, International Baccalaureate, ICSE, CBSE

Subjects taught

History, Economic Application, Hindi, Economics, Science, History and Civics, Chemistry, EVS, Computer Application, Social Science, Mathematics, Physics, Geography

Class 10 Tuition

Class Location

Online class via Zoom

At the Institute

Board

IGCSE, International Baccalaureate, ICSE, CBSE

Subjects taught

Computer Application, English, Geography, Economics, Physics, Computers, Science, Chemistry, Social Science, EVS, Economic Application, History, Mathematics, History and Civics

Reviews

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Answers by Excellence

Answered on 02/10/2018 Learn CBSE - Class 11/Physics

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Rolling Motion is something such that it combines both translation and rotation.
Answers 2 Comments
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Answered on 28/09/2018 Learn CBSE - Class 11/Physics

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Post a Lesson

m = 1000kg u(initial velocity) = 0 ; as the body starts from rest . v( final velocity ) = 54 km/h = 15 m/s t(time) = 5 sec using equation of motion , v = u + at , or 15 = 0 + a*5, or a = (15-0) / 5 so , a = 3 m /s^2 now , we know kinetic energy = 1/2 M V^2 so... ...more

m = 1000kg

u(initial velocity) = 0 ; as the body starts from rest .

v( final velocity ) = 54 km/h = 15 m/s

t(time) = 5 sec

 

using equation of motion ,

v = u + at  , or 

15 = 0 + a*5, or

a = (15-0) / 5 

so , a = 3 m /s^2 

 

now ,  we know kinetic energy = 1/2 M V^2

                                so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .

Answers 2 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

Teaches

Class 11 Tuition

Class Location

Online class via Zoom

At the Institute

Board

International Baccalaureate, CBSE, IGCSE, ISC/ICSE

Subjects taught

Physics, Economics, Mathematics, History, Political Science, Geography

Class 12 Tuition

Class Location

Online class via Zoom

At the Institute

Board

International Baccalaureate, CBSE, IGCSE, ISC/ICSE

Subjects taught

Economics, Geography, Physics, Sociology, History, Political Science, Mathematics, Social science

Class 9 Tuition

Class Location

Online class via Zoom

At the Institute

Board

IGCSE, International Baccalaureate, ICSE, CBSE

Subjects taught

History, Economic Application, Hindi, Economics, Science, History and Civics, Chemistry, EVS, Computer Application, Social Science, Mathematics, Physics, Geography

Class 10 Tuition

Class Location

Online class via Zoom

At the Institute

Board

IGCSE, International Baccalaureate, ICSE, CBSE

Subjects taught

Computer Application, English, Geography, Economics, Physics, Computers, Science, Chemistry, Social Science, EVS, Economic Application, History, Mathematics, History and Civics

No Reviews yet!

Answers by Excellence

Answered on 02/10/2018 Learn CBSE - Class 11/Physics

Ask a Question

Post a Lesson

Rolling Motion is something such that it combines both translation and rotation.
Answers 2 Comments
Dislike Bookmark

Answered on 28/09/2018 Learn CBSE - Class 11/Physics

Ask a Question

Post a Lesson

m = 1000kg u(initial velocity) = 0 ; as the body starts from rest . v( final velocity ) = 54 km/h = 15 m/s t(time) = 5 sec using equation of motion , v = u + at , or 15 = 0 + a*5, or a = (15-0) / 5 so , a = 3 m /s^2 now , we know kinetic energy = 1/2 M V^2 so... ...more

m = 1000kg

u(initial velocity) = 0 ; as the body starts from rest .

v( final velocity ) = 54 km/h = 15 m/s

t(time) = 5 sec

 

using equation of motion ,

v = u + at  , or 

15 = 0 + a*5, or

a = (15-0) / 5 

so , a = 3 m /s^2 

 

now ,  we know kinetic energy = 1/2 M V^2

                                so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .

Answers 2 Comments
Dislike Bookmark
x

Ask a Question

Please enter your Question

Please select a Tag

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