Coaching classes for IB, CBSE, IGCSE & ICSE boards.
Classes - 2 to 12
All subjects including Hindi , Computer & Sanskrit.
Katwaria Sarai, Delhi, India - 110016
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F-68 WELL NO 2
KATWARIA SARAI HAUZ KHAS DELHI
Katwaria Sarai, Delhi, India - 110016
Landmark: well no 2
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Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE, International Baccalaureate, ISC/ICSE, IGCSE
Subjects taught
Geography, Mathematics, History, Economics, Physics, Political Science
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE, International Baccalaureate, ISC/ICSE, IGCSE
Subjects taught
Physics, Social science, Geography, Sociology, Political Science, Economics, History, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, CBSE, ICSE, International Baccalaureate
Subjects taught
Physics, Social Science, Mathematics, Geography, Economics, Hindi, Economic Application, History, Science, Chemistry, EVS, History and Civics, Computer Application
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, CBSE, ICSE, International Baccalaureate
Subjects taught
Chemistry, Geography, English, Social Science, Computer Application, Economics, Economic Application, Mathematics, History, Computers, History and Civics, EVS, Physics, Science
1. Which school boards of of Class 11 do you teach for?
CBSE, International Baccalaureate, ISC/ICSE and others
2. Which classes do you teach?
We teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Class 9 Tuition Classes
3. Do you provide a demo class?
Yes, We provide a free demo class.
4. Where are you located?
We are located in Katwaria Sarai, Delhi.
Answered on 02/10/2018 Learn CBSE/Class 11/Science/Physics
Answered on 28/09/2018 Learn CBSE/Class 11/Science/Physics
m = 1000kg
u(initial velocity) = 0 ; as the body starts from rest .
v( final velocity ) = 54 km/h = 15 m/s
t(time) = 5 sec
using equation of motion ,
v = u + at , or
15 = 0 + a*5, or
a = (15-0) / 5
so , a = 3 m /s^2
now , we know kinetic energy = 1/2 M V^2
so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE, International Baccalaureate, ISC/ICSE, IGCSE
Subjects taught
Geography, Mathematics, History, Economics, Physics, Political Science
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
CBSE, International Baccalaureate, ISC/ICSE, IGCSE
Subjects taught
Physics, Social science, Geography, Sociology, Political Science, Economics, History, Mathematics
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, CBSE, ICSE, International Baccalaureate
Subjects taught
Physics, Social Science, Mathematics, Geography, Economics, Hindi, Economic Application, History, Science, Chemistry, EVS, History and Civics, Computer Application
Class Location
Online (video chat via skype, google hangout etc)
At the Institute
Board
IGCSE, CBSE, ICSE, International Baccalaureate
Subjects taught
Chemistry, Geography, English, Social Science, Computer Application, Economics, Economic Application, Mathematics, History, Computers, History and Civics, EVS, Physics, Science
Answered on 02/10/2018 Learn CBSE/Class 11/Science/Physics
Answered on 28/09/2018 Learn CBSE/Class 11/Science/Physics
m = 1000kg
u(initial velocity) = 0 ; as the body starts from rest .
v( final velocity ) = 54 km/h = 15 m/s
t(time) = 5 sec
using equation of motion ,
v = u + at , or
15 = 0 + a*5, or
a = (15-0) / 5
so , a = 3 m /s^2
now , we know kinetic energy = 1/2 M V^2
so K.E = 1/2 * 1000 *15 *15 = 112500 Joules .
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Katwaria Sarai, Delhi 
