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# What is the integration process of e^x/(1+x) Master of Physics & have excellent skills of Mathematics problem solving

Use LIATE (Logarithmic-Inverse-Algebric- Trignometruc-Expoential Sequence) with u/v rule

such question is solved by using by parts but in this question by parts will not work in fact this not integrable

M.Tech from IIT Bombay(Expert maths Faculty)

Apply ILATE rules (standing for Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential), Integration by parts. Maths Solution

Integration by parts....assuming (e^x ) 2nd function and 1/(1+x) ist function

to solve such type problem, you have to use this method ,if both the functions are directly integrable ,then the first function is chosen in such a way that the derivative of the function thus obtained under integral sign is easily integrable . while doing this if you find this question in the form... read more
to solve such type problem, you have to use this method ,if both the functions are directly integrable ,then the first function is chosen in such a way that the derivative of the function thus obtained under integral sign is easily integrable . while doing this if you find this question in the form of the such function sinx/x, cosx/x ,1/logx , rootsinx , sin(x square ) exp.(x square) exp.(-x square) ,xtanx , and few more ..however these functions are differentiable but integration can not be found read less

Master of Physics & have excellent skills of Mathematics problem solving

You can also solve it using theorem of integration e^x(f(x)+f'(x)). Coaching offers for Classes INTER, XI,XII (CBSE,ISC), IIT, CAT, BANKING EXAMS

both the functions are continuous functions so consider let I=integ function then apply by parts formula

both the functions are continuous functions so consider let I=integ function then apply by parts formula

M.Tech from IIT Bombay(Expert maths Faculty)

Apply ILATE rules (standing for Inverse trigonometric, Logarithmic, Algebraic, Trigonometric, Exponential) integration by parts rule!

firstly.....assuming 1+x=y, then integration by part e^y as 2nd function and 1/y as 1st ffunction

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