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The current in a circuit follows the relation i = 100sin?t. If frequency is 25 Hz, how long will it take for the current to rise to 50 A ? a.) 1 ms. b.) 3.33 ms. c.) 10 ms. d.) 20 ms.

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i= sin wt f= 25 HZ w= 2×pi×f t=? 50=100 sin wt 50=100 sin (2×180×25) t 50/100= sin 9000 t 1/2=sin 9000 t Sin-' (1/2)= 9000t sin -' (1/2)=30 30= 9000 t t = 30/9000 t = 1/300 = 3.33 ms.
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i= sin wt f= 25 HZ w= 2×pi×f t=? 50=100 sin wt 50=100 sin (2×180×25) t 50/100= sin 9000 t 1/2=sin 9000 t Sin-' (1/2)= 9000t sin -' (1/2)=30 30= 9000 t t = 30/9000 t = 1/300 = 3.33 ms. read less
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B) 3.33 ms
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Power To Teach

50=100sin(2pi25) t after solving we get t=3.33ms
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Solution: i = 100 sin(wt) 50=100 Sin(wt) wt = Arc Sin(1/2)= pi/6 radians but w = 2 pi 25hz= 50 pi wt = 50 pi t= pi/6 t= pi/6w= pi/( 6 x 50 pi) = 3.36 ms
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b
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3.33ms
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3.33ms, as for I to be 50A sinwt needs to be half..
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B
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