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Somebody pls explain me about the formative assessment and summative assessment followed by CBSE (for 10th class Maths .)

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google science

its just like semester system. 1 sem 1 syllabus 1 exam and aggregate of all exams will be the total %
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14 years being a Private Tutor as an @Educator-Trainer-Motivator-

There are four FA (1,2,3,4) and two SA (1&2). The session begins with FA 1 consisting of written examination ( either 20 Or 40 marks varies from school to school). Then comes FA 2 consisting of project, cw/hw, class performance , viva etc These are followed by SA 1 which is again written examination...
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There are four FA (1,2,3,4) and two SA (1&2). The session begins with FA 1 consisting of written examination ( either 20 Or 40 marks varies from school to school). Then comes FA 2 consisting of project, cw/hw, class performance , viva etc These are followed by SA 1 which is again written examination of 90 marks. 10% weightage is given to Each FA = 20% 30% weightage is given to SA. = 30% SO TOTAL WEIGHTAGE RECEIVED BY A STUDENT TILL MIDDLE OF THE SESSION IS 50 %. THE SAME THING FOLLOWS FOR THE NEST HALF OF THE SECCION. WHICH SUM UP TO 100%. This is Called the CCE pattern. In this pattern a students final result depends on the whole years performence and not just by a single written test at the end of the year. read less
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Commerce world

Nthing special it is only semester system..
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Tutor

Formative means we have take few chapters only Summative means all the syllabus regarding subject
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Maths, Physics, English,Hindi

Fa1 is ur monthly test and SA is ur h alf yrly
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THERE are 4 FA and 2 SA's
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4 fa and 2 sa's
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Linguist

Summative assessment is used as an evaluation technique in instructional design. It can provide information on an intervention's efficacy (its ability to do what it was designed to do). Summative evaluation judges the worth, or value, of an intervention at its conclusion where as formative assessment...
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Summative assessment is used as an evaluation technique in instructional design. It can provide information on an intervention's efficacy (its ability to do what it was designed to do). Summative evaluation judges the worth, or value, of an intervention at its conclusion where as formative assessment including diagnostic testing is a range of formal and informal assessment procedures conducted by teachers during the learning process in order to modify teaching and learning activities to improve student attainment.[1] It typically involves qualitative feedback (rather than scores) for both student and teacher that focuses on the details of content and performance.[2] It is commonly contrasted with summative assessment, which seeks to monitor educational outcomes, often for purposes of external accountability. read less
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math tutor

its only a saMasters system
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help students identify their strengths and weaknesses and target areas that need work help faculty recognize where students are struggling and address problems immediately Formative assessments are generally low stakes, which means that they have low or no point value. Examples of formative assessments...
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help students identify their strengths and weaknesses and target areas that need work help faculty recognize where students are struggling and address problems immediately Formative assessments are generally low stakes, which means that they have low or no point value. Examples of formative assessments include asking students to: draw a concept map in class to represent their understanding of a topic submit one or two sentences identifying the main point of a lecture turn in a research proposal for early feedback read less
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Related Questions

What happens to the gravitational force between two objects if their masses do not change but the distance between them becomes four times as much?
Gravitational force is inversely proportional to square of distance. Therefore 4 times further, which means 16times less gravitational force or pull between the bodies.
Kumar Upendra Akshay
Dear friends, Please correct me in case I am wrong. I your opinion , what should be the maximum number of students in a coaching class, so that each student can have maximum dedicated time from the attending teacher in the classroom. In present days, cost and time of coaching / tuition matters a lot . The same will be demontrated by the following two examples : Example 1 : Suppose a student pays Rs. 4000/= per month ( 26 days in a month , excluding Sundays ), One hour per day , number of student is only one, then cost of coaching per minute works out to (Rs. 4000/=X 1 Student )/(26 days X 60 min/day ) = Rs.2.56 per min. cost and he will get dedicated time of 60 min. each day to carry on his studies. Example - 2 : Suppose a student pays Rs. 2000/= per month ( 26 days in a month , excluding Sundays ), One hour per day , number of student is 30 in a class, then cost of coaching per minute works out to (Rs. 2000/=X 30 Students in a coaching class ) / (26 days X 60 min/day ) = Rs.38.46 per min. cost and he will get dedicated time of only two min. each day for his studies. The above examples shows that though the monthly fees paid by each student is just half ( Rs. 2000/= see example -2 ) in case of classroom type of coaching as compared to the individual coaching ( Rs. 4000/= see example - 1 ), but on the other side cost of coaching per min. based on true dedicated time is 15 times higher in case of classroom type coaching with mass students than single student coaching. These can be however extrapolated for any number of students in a coaching class. As a result the speed of learning process of a student will be about fifteen times slower in classroom type coaching having mass students in a class ignoring the other factors. However, it may be the choice of the students and parents which option is better for them ? Regards, Sudhansu bhushan Roy.
Sir your calculations are excellent. I would like to add few things. 1. It depends on the student / parents choice at the end. 2. It never implies that effective attention to a student is 2-3 mins, so...
Sudhansu Bhushan R.
A point pole has a strength of 4? × 10-4 weber. The force in newtons on a point pole of 4? × 1.5 × 10-4 weber placed at a distance of 10 cm from it will be a.) 20 N. b.) 15 N. c.) 7.5 N. d.) 3.75 N.
Solution: m1 = 4N × 10^-7, m2 = 4N × 1.5 × 10^-4; r = 10 cm. F= (m1 m2)/( 4 pi mue0 r^2) = (4N 10^-7 x 4N 10^^-4)/(4N x 4N x 10^-7(10 x10^-2)^2 =15N
Kumar Upendra Akshay
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