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Solution to a differential equation asked In engineering CET exam

Profile Photo B.sudhakar
19/02/2017 0 View Comments0

Solve the diff eqn dy/y + dx/x =0

Let's rearrange by shifting x components to right hand side

dy / y = - dx  /x. ( variable seperable eqn )

Integrating both sides

∫ 1/y dy = - ∫ 1/x dx 

= log | y | = - log | x | + log c ( we can multiply constant c with log )

= log | y | = log c - log | x | 

= log | y | = log ( c / x ). ( we can remove log on both sides

= y = c / x or                ( y • x ) = c     and it is the solution 

 

 

 

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