Prove that E= half LI•I

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G Prasad

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Power absorbed or dissipated by an inductor P = dE/dt...'(1) If 'E' is the energy and 't' is time. Voltage drop across inductor = L * dI/dt but P = VI So, dE/dt = L*(dI/dt) *I dE = LIdI Integrating from 0 to E on LHS and 0 to I on RHS E = (1/2) * L *(I^2)
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Headstart to assured 95+ score in math

Please refer NCERT text.
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mc2
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Home Tutor

This is an expression indicating the magneto static potential energy stored in an inductor.we can obtain it in the same way as of getting electrostatic potential energy stored in capacitor
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Brain Trainer

Power absorbed or dissipated by an inductor P = dE/dt and Voltage drop across inductor = L * dI/dt Also, P = VI So, dE/dt = L*(dI/dt) *I So, dE = LIdI Integrating both sides E = (1/2) * L *(I^2)
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Please refer NCERT text.
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