0Now tan ( A + B ) = tan A + tan B/1— tan A tan B
Put B = A
= tan ( A + A ) = tan ( 2A )= tan A + tan A / 1 — tan A tan A
= 2 tan A / 1 — tan² A
∴ tan (2A)= 2 tan A / (1 — tan² A)
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Now tan ( A + B ) = tan A + tan B/1— tan A tan B
Put B = A
= tan ( A + A ) = tan ( 2A )= tan A + tan A / 1 — tan A tan A
= 2 tan A / 1 — tan² A
∴ tan (2A)= 2 tan A / (1 — tan² A)
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