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# Important question of Atom and nuclie 1 Find expression for atomic radius 2 Find expression for energy 3 what is deBroglie equation

Tutor

the de Broglie wavelength of a moving particle is equal to the Planck constant divided by the momentum of the particle.

Teacher

Atoms of alkali metals are stacked in such a way as to form a body-centered cubic. There are 8 sections of an atom at the corner and one full one at the center. If you imagine stacking several of these blocks, you ll realize that each corner is adjacent to seven others, so that each corner represents... read more
Atoms of alkali metals are stacked in such a way as to form a body-centered cubic. There are 8 sections of an atom at the corner and one full one at the center. If you imagine stacking several of these blocks, you’ll realize that each corner is adjacent to seven others, so that each corner represents 1/8th of an atom. The cell therefore represents 8(1/8) + 1 central = 2 atoms. 1. Write a formula for the mass of these two atoms in terms of molar mass and Avogadro’s number. m = 2 atoms(mole/(6.022 X1023 atoms)( M g/mole) = 2M/NA where M = molar mass NA= Avogadro’s number read less

Broglie wavelength of a moving particle is equal to the Planck constant divided by the momentum of the particle.

Bachelor of Engineering (B.E.) in Electronics & Communication

de Broglie equation. the postulate of wave mechanics that a particle of mass m moving at a velocity v will have the properties of a wave of wavelength h/mv (de Broglie wavelength) where h is Planck's constant.

Math Expert Educator and Spoken English Trainer with 12 Years Experience of Teaching and Educating.

lambda = h/mv means that with any object that has a momentum (mv), there is an associated wave of wavelength lambda h is Planck's constant.

Chemistry Wizard/English Expert

https://chemistry.osu.edu/~woodward/ch121/ch2_atoms.htm

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