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# If the temperature of the cold body is decreased the efficiency of a carnot engine __________. (Decreases, Increases, Remains constant)

Increases

Expert in IIT NEET entrance exams

Efficiency = 1 - (T1/T2) T1 temp of sink T2 temp of source As T1 decrease T1/T2 ratio decrease So efficiency increased

Decrease

The efficiency of the Carnot engine is given by eeta = 1- T2 / T1 now; if T2 increase, eeta mill decrease. But if T1 increase, then eeta will increase.

Decrease because T2-T1 will increase and so will the efficiency. But remember, like all other properties, after a complete cycle, the entropy of the working gas in the system will be same as before. We are only talking of the difference in the entropy change of the universe. As the engine will now...
Decrease because T2-T1 will increase and so will the efficiency. But remember, like all other properties, after a complete cycle, the entropy of the working gas in the system will be same as before. We are only talking of the difference in the entropy change of the universe. As the engine will now be doing more work for same heat consume read less

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Increases

Increases

Decreases

Increase

M. Tech holder with 9 years of teaching experience

Carnot cycle eff 1-(T2/T1) Here T2 is the cold body temp If T2 is decreased T2/T1 will be decreased . If T2/T1 is decreased then 1-T2/T1 will be increased. So the answer is "increases"

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