identify the region |z-2|<8&|z-1|<|z-5|

Asked by Last Modified  

6 Answers

Follow 0
Answer

Please enter your answer

Expert In Our Work

first we have to change inequality sign to equality sign.then |z-2|=8 represent a circle whose center lies on real axis in argand plane at (2,0) with radius 8.in complex no. |z-q| represent distance b/w two points.so when we interchange inequality with equality in second equation we get |z-1|=|z-5|.this...
read more
first we have to change inequality sign to equality sign.then |z-2|=8 represent a circle whose center lies on real axis in argand plane at (2,0) with radius 8.in complex no. |z-q| represent distance b/w two points.so when we interchange inequality with equality in second equation we get |z-1|=|z-5|.this says that distance of point z from pt. (-1,0) and from (-5,0) equal so the locus of z is a straight line which is perpendicular bisector of pt.(-1,0) &(-5,0) this is passes through mid point of these two points so the mid pt. is (-3,0) . this line also cuts the circle for identify the region we take any point (0,0) and put put this in both the equation if it satisfy both the inequality then the region is lies right side of the line . read less
Comments
Dislike Bookmark

IIT Educated and well experienced experts selecting only a few highly motivated and ambitious students

|z-2| < 8, let z = a + bi, with i = sqrt(-1) | (a + bi) - 2| < 8 | (a-2) + bi| < 8 sqrt < 8 ( a - 2) ^2 + b ^2 < 64 This region describes a circle of radius 8 centered at (2,0) in the complex plane. |z-1| < |z-5| (a-1)^2 + b^2 < (a-5)^2 + b^2 (a - 1) ^ 2 - (a-5)^2 < 0 4(2a - 6)...
read more
|z-2| < 8, let z = a + bi, with i = sqrt(-1) | (a + bi) - 2| < 8 | (a-2) + bi| < 8 sqrt [ (a-2) ^ 2 + b ^ 2 ] < 8 ( a - 2) ^2 + b ^2 < 64 This region describes a circle of radius 8 centered at (2,0) in the complex plane. |z-1| < |z-5| (a-1)^2 + b^2 < (a-5)^2 + b^2 (a - 1) ^ 2 - (a-5)^2 < 0 4(2a - 6) < 0 (a-3) < 0 a<3 The region described is the entire complex plane with real part less than 3. Hope this helps Cheers read less
Comments
Dislike Bookmark

Expert In Our Work

Sandeep 9 hours ago first we have to change inequality sign to equality sign.then |z-2|=8 represent a circle whose center lies on real axis in argand plane at (2,0) with radius 8.in complex no. |z-q| represent distance b/w two points.so when we interchange inequality with equality in second equation...
read more
Sandeep 9 hours ago first we have to change inequality sign to equality sign.then |z-2|=8 represent a circle whose center lies on real axis in argand plane at (2,0) with radius 8.in complex no. |z-q| represent distance b/w two points.so when we interchange inequality with equality in second equation we get |z-1|=|z-5|.this says that distance of point z from pt. (-1,0) and from (-5,0) equal so the locus of z is a straight line which is perpendicular bisector of pt.(-1,0) &(-5,0) this is passes through mid point of these two points so the mid pt. is (-3,0) . this line also cuts the circle for identify the region we take any point (0,0) and put put this in both the equation if it satisfy both the inequality then the region is lies right side of the line . read less
Comments
Dislike Bookmark

Mathematics for JEE Mains/Advanced, XI & XII (All Boards)

Circle with center (2,0) and radius 8.
Comments
Dislike Bookmark

Mathematics for JEE Mains/Advanced, XI & XII (All Boards)

For the other one, distance of z from 1 should be less than distance from 5.
Comments
Dislike Bookmark

SME in Mathematics & Statistics

|z-2|<8 ? (x -- 2)2 + y2 < 64 The area (x -- 2)2 + y2 < 64 is interior of the circle (x -- 2)2 + y2 = 64. The circle (x -- 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x -- 1)2 < (x -- 5)2 ? 1 -- 2x < 25 -- 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight...
read more
|z-2|<8 ? (x – 2)2 + y2 < 64 The area (x – 2)2 + y2 < 64 is interior of the circle (x – 2)2 + y2 = 64. The circle (x – 2)2 + y2 = 64 has centre (2, 0) and radius 8. |z-1|<|z-5| ? (x – 1)2 < (x – 5)2 ? 1 – 2x < 25 – 10x ? 8x < 24 ? x < 3 The area x < 3 is marked to the left of the straight line x = 3. The line x = 3 is parallel to y axis intersecting x axis at (3, 0). The resultant area will be the common intersection zone of the above two areas. read less
Comments
Dislike Bookmark

View 4 more Answers

Related Questions

A company has a loan of Rs.15,00,000 as part of its capital employed. The interest payable on Loan is 15% and the ROI of the company is 25%. The rate of income tax is 60%. What is the gain to shareholders due to the loan raised by the company?
ROI = EBIT/ Capital EmployedEBIT = ROI × Capital Employed = 25% × 20,00,000 = 5,00,000 Intrest = 20,00,000 × 15% = 3,00,000 Shareholders Gain = EAT ( Earning After Tax) = (EBIT - Intrest)...
Nazia
0 0
View Comments7
What is differenc between enthalpy and entropy ?
Entropy is a measure of disorder or randomness of a system. For example An ordered system has low entropy where as Enthalpy is defined as the sum of internal energy of a system and the product of the pressure and volume of the system.
Yogesh Thakare
AM and GM are quite different from each other and these are non negative so it cant follow the negative sign .
AM and GM are quite different from each other and these are non negative so it cant follow the negative sign only it can not be change
Suman
The radiation emitted from hydrogen filled discharge tube, when viewed by dispersing devices such as prism, gratings etc, shows __________. (A line spectrum, Continuous spectrum, Linear spectrum, all of these)
all of these
Narendra Kumar
0 0
View Comments6
What is your throuout success rate in preparing JEE exam students?
2%
Bala

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Work the Smarter Way
In a nutshell: the best study tips are those that train your brain to work smarter instead of harder, help you optimize your study time, and take advantage of shortcuts whenever possible. These 5 tips...
R

Rahul

0 0
View Comments0
Chemistry- Lewis Concept Of Acids And Bases.
Explain the Lewis concept of acids and bases.A Lewis acid is, therefore, any substance, such as the H+ ion, that can accept a pair of nonbonding electrons. In other words, a Lewis acid is an electron-pair...

Nidhi T.

0 0
View Comments0
Introduction To Accounting: Part 1: Need For Accounting
Whenever we start doing business, a number of transactions take place. For example, if we start a business of say, a book store (i.e. we’ll be buying books from wholesalers and publishers, and selling...

Nishant Kumar

0 0
View Comments0
ELECTROCHEMISTRY
(a) The process of chemical decomposition of an electrolyte on the passing of electric current through its aqueous solution or in its molten state is known as electrolysis.(b) It involves oxidation...

Chandra Shekar

0 0
View Comments0
Vedic Mathematics for Multiplication of two 2-digited numbers
Vedic Mathematics is a very powerful tool for us to get quick calculations For Multiplication of two 2-digited numbers, we can follow FOIL technique. If you want to multiply 74×36(let's present...
N

Naimish K.

0 0
View Comments0

Recommended Articles

Meet Radhe Shyam Burman, an MBA Tutor from...

Radhe Shyam is a highly skilled accounts and finance trainer with 8 years of experience in teaching. Accounting is challenging for many students and that’s where Radhe Shyam’s expertise comes into play. He helps his students not only in understanding the subject but also advises them on how to overcome the fear of accounts...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Urmila, an MBBS tutor from Bangalore

Urmila is a passionate teacher with over 8 years of experience in teaching. She is currently pursuing her Ph. D. She provides classes for Class 11, Class 12, MBBS and Medical tuition.  Urmila began her career in teaching long before she became a teacher. She used to provide classes for foreign national students in her college...

Read full article >

Find Class 12 Tuition near you
Class 12 Tuition in Delhi
Class 12 Tuition in Bangalore
Class 12 Tuition in Hyderabad
Class 12 Tuition in Mumbai
Class 12 Tuition in Chennai
Class 12 Tuition in Kolkata
Class 12 Tuition in Pune
Class 12 Tuition in Jaipur
Class 12 Tuition in Noida
Class 12 Tuition in Gurgaon
Online Tuition Class 12

Looking for Class 12 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you