fees of a mathematics teacher cls 12 ?

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Tutor

800-1000 per hour
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Home Tutor

450 per hour.
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Rs.500 to 1000 per hour depending upon the fact whether you r teaching just CBSE or training your student for higher competitive exams like JEE as well.
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Maths Tutor

500 to 600 per hour.
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Home tution - 5K Tutorial:- 2-3K
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5,000 PM. for home tution with 25 working days (1 hr /day).
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Physics and Maths Tutoring up to college level

It depends on your experience and quality of teaching. Provide a demo session (free) and assess the payment ability of the client. Based on that and your other charges (such as travel, equipments etc) you can charge upto ?600/hr. Note: such charges will be only accepted by the client if you're am excellent...
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It depends on your experience and quality of teaching. Provide a demo session (free) and assess the payment ability of the client. Based on that and your other charges (such as travel, equipments etc) you can charge upto ?600/hr. Note: such charges will be only accepted by the client if you're am excellent teacher. read less
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3000-4000 per month... depending on the distance
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Commerce & Management Tutor

Rs 2000 per month
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Tutor

4000
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What is the equation of tangent and its slope form?
m= the slope of the tangent= dy/dx Tangent A: y= mx + square root( square of (am) + square of b), where m=the slope of the tangent=dy/dx or at (x1, y1), xx1/square of a + yy1/square of b=1. c = sqrt (a*a*m*m + b*b).
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Chitra
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What do you mean by locus of the point?
The set of all points. This usually results in a curve or surface with base point as focus (center basis point).
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Nitin
What is focal chord?
If a line be drawn through the focus and parallel to the directrix, it will intersect the parabola at two points that lie a distance 2 p from the focus. The line segment connecting these two points is called the focal chord.
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Ganesh
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Recursion Basics ..How to find solution of F(n) in terms of F(n-1) example of square
https://vz-3ad30922-ba4.b-cdn.net/10e5f2a9-0e3e-4fa6-a08b-a2697325c9d9/play_480p.mp4
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For Positive Integers X And Y; 3x + 8y = 68. Find The Maximum Value Of x^2*y^3.
Question: For positive integers x and y; 3x + 8y = 68. Find the maximum value of x^2*y^3. Answer: Method 1: 3x +8y = 68; x = (68-8y)/3i.e for y = 1; x = 20Hence y's values will increase in step of...
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IIT JEE Advanced/Mains Syllabus
Complex Number Algebra of complex numbers, addition, multiplication, conjugation. Polar representation, properties of modulus and principal argument. Triangle inequality, cube roots of...
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