Differentiate with respect to x: xy = log y + C?

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If y is constant then answer is 0. But if y is again function of x, then y + xy' = y - 1y'.
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x(derivative of y) + y(derivative of x) = derivative of (log y) + derivative of C. remember C is a constant. So, xy' + y=y'/y + 0 --> xy' + y = y'/y.
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(y power 2)/(1-xy).
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Maths teacher. Have started teaching online now

y+xy'= y'/y.
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