A die is thrown 360 times .prime number appears on the upper face 39 times. If the die is thrown at random, what is the probability of getting a prime number.

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Among six numbers (1,2,3,4,5,6) labelled on the die, 2,3 and 5 are prime numbers. Therefore, if the die is perfectly designed, the probability that a prime number will come up is 1/2. One has to calculate using the formula for mean deviation and see if 39/360=13/120 being the probability observed as...
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Among six numbers (1,2,3,4,5,6) labelled on the die, 2,3 and 5 are prime numbers. Therefore, if the die is perfectly designed, the probability that a prime number will come up is 1/2. One has to calculate using the formula for mean deviation and see if 39/360=13/120 being the probability observed as above is within the error bar. read less
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please answer.
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Sample space is 6^360 Probability of getteing a prime number = 39/6^360
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Spoken English, BTech Tuition, C Language, C++ Language, CAD etc., with 4 years of experience

39/6^360
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Probability of getteing a prime number = 39/6^360
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