A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, then the fraction of the work that is left is : A.1/4 B.1/10 C.7/15 D.8/15

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A's 1 day work=1/15, B's= 1/20, Combined 1-day work=(1/15 + 1/20= 7/60); Combined 4 day's work= 28/60, therefore work left=(1-28/60)=32/60 or 8/15
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A's 1 day's work = 1 ; 15 B's 1 day's work = 1 ; 20 (A + B)'s 1 day's work = ( 1 + 1 ) = 7 . 15 20 60 (A + B)'s 4 day's work = ( 7 x 4 ) = 7 . 60 15 Therefore, Remaining work = ( 1 - 7 ) = 8 . 15 15 ans: 8/15
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A's 1 day's work = 1 ; 15 B's 1 day's work = 1 ; 20 (A + B)'s 1 day's work = ( 1 + 1 ) = 7 . 15 20 60 (A + B)'s 4 day's work = ( 7 x 4 ) = 7 . 60 15 Therefore, Remaining work = ( 1 - 7 ) = 8 . 15 15 ans:8/15
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A does 1/15th work per day B does 1/20th of whole work in one day total work done by a and b together in one day = (1/15)+(1/20) total work done by a and b together in 4 days = 4* remaining work = 1 - 4* =32/60 =8/15
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Don't want to over express myself, just join and feel the experience.

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The answer is option D. 8/15
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