A box contains 5 nails and 12 nuts. Half of the nails and half of the nuts are rusted. If one item is chosen at random then find the probability that it is rusted and is a nail?

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Sumit Jha

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first find the probability of getting a rusted and then find the probability of getting a nail!!!
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Expert Mathematics & Science Educator | Grades 8-12 | Personalized Learning & Academic Excellence

P(rusted) = 8/16 P(nail) = 6/16 P(rusted and nail) = 3/16 P(A intersection B) = 8/16 + 6/16 - 3/16;
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Physics and Maths made easy

The question carries an error! There are five nails and half of 5 is 2.5. It is now a meaningless assertion to say 2.5 nails (question says half of the nails and half of the nuts are rusted) are rusted. Kindly rectify the mistake and forward it once again.
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Spoken English, BTech Tuition, C Language, C++ Language, CAD etc., with 4 years of experience

5/2 nails. But doesn't make sense
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Half of 5 nails is not possible.
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Job experience of 1 year in an MNC, B.Tech with Diploma in Business Management

If you want you can consider the other half nail as 3rd rusty nail and proceed if you really want to consider and solve the question...!!!
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Data Analytics & Advanced Statistics Tutor with 18 years of experience in teaching

No.of nails in box is incorrect to the second sentence in the question.
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Online Tutor-Mathematics, Science, Competitive Exam Preparation

Half of 5 nails??
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Trainer

I think, half of the nails = 5/2 which is not appropriate, because counting nails cannot be a fraction
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Tutor - Maths and computer science

P(rusted) = 8/16 P(nail) = 6/16 P(rusted and nail) = 3/16 P(A intersection B) = 8/16 + 6/16 - 3/16 =11/16
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