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4 cards are drawn from a well shuffled deck of 52 cards. what is the probability of obtaining 3 diamonds and one spade ?

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The probability of getting 3 diamonds=13C3 the Probability of getting 1 spade=13C1 And total outcome=52C4 So probability of getting 3 diamonds and 1 spade=(13C3 * 13C1)/52C4. final answer will be 858/62475..
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The probability of getting 3 diamonds = 13C3. The Probability of getting 1 spade = 13C1 And total outcome = 52C4 So probability of getting 3 diamonds and 1 spade = (13C3 * 13C1)/52C4. final answer will be 858/62475..
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(52C3 X52C1)/52C4
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Pursuing my IAS goal since 2010-11

13/52*12/52*11/52*13/52........................in total 52 cards both diamond and spade are 13 each. so when he draws 1st card it being diamond out of total card is 13/52,succintly 2nd card being diamond is 12/52..............and so on
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Native English Speaker with 32 years experience in teaching English and communication skills.

858/62475
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858/62475
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13c3x13c1/52c4
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Teaching is my passion!!!!

858/62475
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Application oriented with 10 yrs exp

divided by 52C4
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Teaching because it is fun

4 cards from a pack of 52 can be drawn in 52C4 ways 3 Diamonds can be drawn from the available 13 Diamonds in 13C3 ways, and 1 Spade can be drawn from the available 13 Spades in 13C1 ways. Therefore, the answer is, (13C3 X 13C1) / 52C4
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