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Class 10 > The emf of a cell is always greater than its terminal...
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The emf of a cell is always greater than its terminal voltage. Why? Give reason.

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The terminal voltage is measured in closed circuit (while current is drawn) and in this stage internal resistance of cell becomes active which lowers the potential difference across the terminals, The emf is measured when circuit is open (current is not drawn) and hence internal resistance remains inactive....
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The terminal voltage is measured in closed circuit (while current is drawn) and in this stage internal resistance of cell becomes active which lowers the potential difference across the terminals, The emf is measured when circuit is open (current is not drawn) and hence internal resistance remains inactive. This is the reason why emf is more than the terminal voltage. read less
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Terminal voltage, V=E-Ir . Where E=emf and I=current, r=internal resistance of the cell. Whenever current flows through cell, some voltage drop occurs across the internal resistance of the cell. This voltage drop is proportional to the current flowing through the cell. Hence, the terminal voltage is...
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Terminal voltage, V=E-Ir . Where E=emf and I=current, r=internal resistance of the cell. Whenever current flows through cell, some voltage drop occurs across the internal resistance of the cell. This voltage drop is proportional to the current flowing through the cell. Hence, the terminal voltage is always less than the emf of the cell. Same thing happens in A.C. and D.C. generators also. This is broadly related to the voltage regulation of any voltage source. read less
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Terminal voltage is the potential difference at the terminals of the circuit. Even if there is no load, still the terminal voltage will be less than the emf due to drop across the internal resistance of the supply. We write this as, E = V+Ir Where, E is the emf, V is the terminal voltage and...
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Terminal voltage is the potential difference at the terminals of the circuit. Even if there is no load, still the terminal voltage will be less than the emf due to drop across the internal resistance of the supply. We write this as, E = V+Ir Where, E is the emf, V is the terminal voltage and r is the internal resistance. read less
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