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Simplify: log base 6 (216) + [log (42) - log (6)] / log (49)?

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CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition Logarithms

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216 = 6^3; log 42 - log 6 = log (42/6) = log 7 ; / log (49) = log 7 / 2 log 7 = 1/2 ; Answer = 3 + 1/2 = 3.5
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diploma in computer engineering

=log? 6/ log? 6^3+{log42-log? 6} /log?7^2 =log6/3log 6+{log(42/7)}/2 log7 =3/2 is ans you got it
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3.5
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log base 6 ( 6^3) + = 3 + log 7 / 2 log 7 = 3 + 1/2 =3.5
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2593/2
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