Simplify: log base 6 (216) + [log (42) - log (6)] / log (49)?

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Muraleedharan R

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216 = 6^3; log 42 - log 6 = log (42/6) = log 7 ; / log (49) = log 7 / 2 log 7 = 1/2 ; Answer = 3 + 1/2 = 3.5
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log base 6 ( 6^3) + = 3 + log 7 / 2 log 7 = 3 + 1/2 =3.5
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=log? 6/ log? 6^3+{log42-log? 6} /log?7^2 =log6/3log 6+{log(42/7)}/2 log7 =3/2 is ans you got it
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15+ Years EXP in Industry & Mentor of AIRs: 1, 2, 5, 10, 17, 20, 49, 56 & 77

Using the properties of Log we can solve it like thislog base 6 ( 6^3) + =3 + log 7 / 2 log 7 = 3 + 1/2 =3.5
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