Find the value of (sin°45- cos°45)

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Salman Ahmad Siddiqui

CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

At 45° sin = cos tan = cot sec = cosec so sin 45° - cos 45°=0
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Teacher

Sin 45 = p/h and cos 45 = b/h It is clear that if one angle is 45, the other must also be the same in a triangle. In other words p = b Therefore p/h - b/h = (p-b)/h = 0/h = 0 Ans
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Sin45degree1/√2 Cos45degree=1/√2 =1/√2-1/√2=0
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Chemistry Teacher

Sin 45 - cos 45 1/(√2) - 1/(√2) 0 ans
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Trainer

(Sin45degree-cos45degree) =(1/root2-1/root2) =0 Thank you
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Sin 45 - Cos 45= 1/√2 - 1/√2= 0
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Tutor

Zero
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Tutor

0.
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Sin45=1/√2 and cos 45= 1/√2 so,sin 45 -cos45= 1/√2-1/√2=0
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