Can u please solve this question? Under root x plus y=7, and x plus under root y=11

Asked by Last Modified  

37 Answers

Follow 1
Answer

Please enter your answer

Pankaj Kumar

BE(Electronics)

Squaring First equ both side (Under root x+y)^2=7^2 then we get x+y=49 then y=49-x -----Equ. No.----(3) Squaring Second equ both side ^2=11^2 we get x^2+y=121 putting the value y from (3) equ. X^2+(49-X)=121 after solving we get X^2-X+49-121=0 then X^2-X-72=0 Using factorization splitting...
read more
Squaring First equ both side (Under root x+y)^2=7^2 then we get x+y=49 then y=49-x -----Equ. No.----(3) Squaring Second equ both side [x+(under root y)]^2=11^2 we get x^2+y=121 putting the value y from (3) equ. X^2+(49-X)=121 after solving we get X^2-X+49-121=0 then X^2-X-72=0 Using factorization splitting middle term we get X^2-9X+8X-72=0 then X(X-9)+8(x-9)=0 then (x-9)(x-8)=0 then (X-9)=0 or (X+8)=0 Hence X=9 or X=-8 Answer read less
Comments
Dislike Bookmark

A Private Tutor of Mathematics

from the , you have x+Y=49,and from the second, you have root y=11-x, which gives y=(11-x)suare. put this y in x+y=49. then you will get a quadratic equatn of x. solve it and get the answer
Comments
Dislike Bookmark

Abhishek S ( M.Pharm.MBA) tutor for IB/International/IGCSE

square it and use simultaneous form
Comments
Dislike Bookmark

Teaching Maths in The Doon School,Dehradun & an ex-employee of The Princeton Review.

Since we have ?x and a y in one equation and ?y and a x in the other, x and y must be positive(because u cannot hav a negative value inside the Sq Root), Since ?x + y = 7, then y ? 7 Since x + ?y = 11, then x ? 11 Assuming x and y are perfect squares(because u cannot hav a negative value inside...
read more
Since we have ?x and a y in one equation and ?y and a x in the other, x and y must be positive(because u cannot hav a negative value inside the Sq Root), Since ?x + y = 7, then y ? 7 Since x + ?y = 11, then x ? 11 Assuming x and y are perfect squares(because u cannot hav a negative value inside the Sq Root), we try the following: x = 0, 1, 4, 9 y = 0, 1, 4 The only values that work are x = 9, y = 4 ?x + y = ?9 + 4 = 3 + 4 = 7 x + ?y = 9 + ?4 = 9 + 2 = 11 Implies x=9 and y=4 Please correct me if there is something wrong. read less
Comments
Dislike Bookmark

Physics Tutor

y = 4 and x = 9
Comments
Dislike Bookmark

Computer Expert

x=9,y=4
Comments
Dislike Bookmark

Programmer

x=9 y=4
Comments
Dislike Bookmark

x+?y=11... . . ?x+y= 7....... . from equation ?y=11--x .so y= 121--22x+x^2 we can substititute this value of y in equation ?x +121 --22x+x^2=7 ?x = --121+-22x--x^2+7 solving irt by trial & error method if WE HAVE x==9 THEN, WE HAVE LHS=?x==?9==3.............. & RHS=-121...
read more
x+?y=11... .[.1 ] . ?x+y= 7.......[2] . from equation [1] ?y=11--x .so y= 121--22x+x^2 we can substititute this value of y in equation[2] ?x +121 --22x+x^2=7 ?x = --121+-22x--x^2+7 solving irt by trial & error method if WE HAVE x==9 THEN, WE HAVE LHS=?x==?9==3..............[A] & RHS=-121 +[22X9]--81= -121 +198 -81= 3...[B] COMPARING BOTH QUANTITITIES WE FIND LHS=RHS HENCE x=9 is the correct solution Now we can have y=7--?x= 7--?9=7--3=4 hence the required value 0f x=9 & y=4 read less
Comments
Dislike Bookmark

By simple substitution we can find x = 9 and y = 4
Comments
Dislike Bookmark

B.tech m.tech from nit with 20 yrs of teaching experience.

X=9 y=4
Comments
Dislike Bookmark

View 35 more Answers

Related Questions

"दुष्कराण्यपि" what is the meaning of this line ?
bad temper
Renu
How much should one charge on hourly basis/ student for a group tuition (5 - 10 group of students) of for (VI - VIII standard - all subjects) and (IX - X - science, social, Hindi, English & Sanskrit)? - Place Mumbai (Central line)
Are you looking for online tuition ?
Juhi
The radius of a hemisphere is r. What is its volume?
2pie r^2
Nandini
0 0
5
What is Discipline?
In natural, discipline is systematic instruction intended to train a person, sometimes literally called a disciple, in a craft, trade or other activity, or to follow a particular code of conduct or "order"....
Pavitra
what is homologous series?
A homologous series is a series of carbon compounds that have different numbers of carbon atoms but contain the same functional group. For example, methane, ethane, propane, butane, etc. are all part of...
Dr. Anshu

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Reflection Of Light (Questions)
Reflection of Light Rays on a Reflecting Surface: When a light ray strikes a surface separating two media with different optical properties, part of the light energy is reflected back to the media where...

Soumi R.

2 0
0
Building own study notes
My philosophy has always been in support of active learning by encouraging students to build their own set of study notes u. Many of my students have secured good marks by creating their own notes .I...
R

Rudhan S.

0 0
0
Hindi Vovels
Hindi Vowels ? ? ? ? ? ? ? ? ? ? ? a ? i ? u ? ? e ai o au This is the letter ?a. It looks kind of like a 3 with a capital T after it and then a little small line in the...

Rajesh Kumar

3 0
0
Bonding
Definition: Bonding is the the force between molcules or elements which bind these elements. Types: There are many types of bonding such as: covelent bonding, ionic bonding, cordinate bonding, hydrogen bonding, etc.
M

Memona I.

0 0
0
Tips to learn formulae
Difference of Squares a2 - b2 = (a-b)(a+b) Difference of Cubes a3 - b3 = (a - b)(a2+ ab + b2) Sum of Cubes a3 + b3 = (a + b)(a2 - ab + b2)
A

Ayushi Garg

0 0
0

Recommended Articles

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Meet Sandhya R, a B.Sc tutor from Bangalore

Sandhya is a proactive educationalist. She conducts classes for CBSE, PUC, ICSE, I.B. and IGCSE. Having a 6-year experience in teaching, she connects with her students and provides tutoring as per their understanding. She mentors her students personally and strives them to achieve their goals with ease. Being an enthusiastic...

Read full article >

Find Class 10 Tuition near you
Class 10 Tuition in Delhi
Class 10 Tuition in Bangalore
Class 10 Tuition in Hyderabad
Class 10 Tuition in Kolkata
Class 10 Tuition in Chennai
Class 10 Tuition in Mumbai
Class 10 Tuition in Pune
Class 10 Tuition in Noida
Class 10 Tuition in Lucknow
Class 10 Tuition in Gurgaon
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you