A sum of money is invested at C.I. table annually, the interest on successive years is Rs. 225 & Rs.240. Find the rate of interest and also the original sum of money?

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Arindam Das

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Sum of Money=Rs.3375; Rate of Interest=6.66%
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CI in 2nd year - CI in 1st year = interest on CI in 1st year CI in 2nd year is : 240 CI in 1st year is : 225 Interest on CI in 1st year is = PNR/100 (here P = 225, N=1, R=?) 240-225 = 225*1*R/100 15=225*R/100 R = (100 *15)/225 = 20/3 =6.66 % Finding the Original Sum For 1st year : Here P =...
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CI in 2nd year - CI in 1st year = interest on CI in 1st year CI in 2nd year is : 240 CI in 1st year is : 225 Interest on CI in 1st year is = PNR/100 (here P = 225, N=1, R=?) 240-225 = 225*1*R/100 15=225*R/100 R = (100 *15)/225 = 20/3 =6.66 % Finding the Original Sum For 1st year : Here P = ?, R = 20/3 (as found above), N=1,CI = 225 225 = P *1 *20 / 3*100 P = 225 *100 *3/20 = Rs. 3375 read less
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Rate of interest is 6 2 3 %
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Rate of interest is 6 2 3 % and original sum of money is Rs.3375
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