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Class I-V Tuition > If 9sinA+40cosA=41 than Find the value of cosA and sinA
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If 9sinA+40cosA=41 than Find the value of cosA and sinA

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Iam an IITIan

cosA = 40/41 and sin A = 9/41
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sinA=1/9 and cosA= 1
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math magician , guitarist, singer, painter

cosA = 40/41 and sin A = 9/41
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9sinA=41-40cos A cosA=40/41 SinA cosA= 9/41
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40 CosA = 41- 9 SinA Square both side , then substitute cos Sq A by Sin sq A. and solve the equation
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Here is the problem: What is the value of sin(A-b) if tan A = 9/40 and A is in the first quadrant, while cos B = -4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just...
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Here is the problem: What is the value of sin(A-b) if tan A=9/40 and A is in the first quadrant, while cos B=-4/5 and B is in the third quadrant? I really don't get this homework. What is up with A and B? Do we need to plot the graph as well? =========================== Here's the one I just did with the same angles. ------------ If tan A=9/40, A is in the first quadrant, cos B=-4/5, B is in the third quadrant, find the value of cos(A+B) -------------- Find the cos(A) Tan=y/x Plot the point (40,9) --> hyp = sqrt(40^2 + 9^2) = 41 cos(A) = x/hyp = 9/41 ------------- cos(A + B) = cosA*cosB - sinA*sinB (from Wikipedia) Find sin(A) and sin(B) ------- sin(A) = y/hyp = 40/41 sin(B) = -3/5 in Q3 (it's the 3, 4, 5 triangle) -------------- cos(A + B) = cosA*cosB - sinA*sinB = (9/41)*(-4/5) - (40/41)*(-3/5) = -36/205 + 120/205 = 84/205 ============================= Use some of the values found in the previous problem: sin(A-b) = sin(A)cos(B) - cos(A)sin(B) = (40/41)*(-4/5) - (9/41)*(-3/5) = -200/205 + 27/205 = -173/205 ------------ What is up with A and B? Angles A & B are measured from the x-axis counter-clockwise. All angles on the x-y plane are measured that way. ------ Do we need to plot the graph as well? You don't have to if you don't want to. Not much to graph, just a point for each angle. For A draw a line from the Origin to (40,9) For B it's to (-3,4) read less
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fitherity subject teacher

cosA =39/40 and sin A=15-41
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cosA=40/41 and sinA=9/41
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A Teacher.

coaA=40/41,sinA=9/41
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