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# Simplify and solve the linear equation

3(5z − 7) − 2(9z − 11) = 4(8z − 13)−17 ⇒ 15z − 21 − 18z + 22 = 32z − 52 − 17 (Opening the brackets) ⇒ −3z + 1 = 32z − 69 ⇒ −3z − 32z = −69 − 1 ⇒ −35z = −70 ⇒

3(5z − 7) − 2(9z − 11) = 4(8z − 13)−17

⇒ 15z − 21 − 18z + 22 = 32z − 52 − 17 (Opening the brackets)

⇒ −3z + 1 = 32z − 69

⇒ −3z − 32z = −69 − 1

⇒ −35z = −70

Engineering graduate from NIT Calicut, Rank holder (#47) in State Entrance Examination.

3(5z-7)-2(9z-11)=4(8z-13)-17 15z-3*7-2*9z+2*11=4*8z-4*13-17 15z-21-18z+22=32z-52-17 -3z+1=32z-69 32z+3z=69+1 35z=70 z=70/35=2

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