A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third, and final day was respectively 1094, 1812, 2050, and 2751. Find the total number of tickets sold on all the four days.

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No. of tickets sold 1st day = 1094 No. of tickets sold on 2nd day = 1812 No. of tickets sold on 3rd day = 2050 No. of tickets sold on 4th day = 2751 Total no. of tickets sold = 1094+1812+2050+2751 = 7,707. Therefore, total tickets sold on all the four days is 7,707.
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Tickets sold on 1st day = 1094 Tickets sold on 2nd day = 1812 Tickets sold on 3rd day = 2050 Tickets sold on 4th day = 2751 Total tickets sold = 1094 + 1812 + 2050 + 2751 ∴ Total tickets sold = 7,707
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Tickets sold on 1st day = 1094 Tickets sold on 2nd day = 1812 Tickets sold on 3rd day = 2050 Tickets sold on 4th day = 2751 Total tickets sold = 1094 + 1812 + 2050 + 2751 ∴ Total tickets sold = 7,707 read less
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