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Two identical circular loops P and Q, each of radius r and carrying equal currents are kept in the parallel planes having a common axis passing through O. The direction of current in P is clockwise and in Q is anti-clockwise as seen from O which is equidistant from the loops P and Q. Find the magnitude of the net magnetic field at O.

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To find the magnitude of the net magnetic field at point O due to the two identical circular loops P and Q, we can use the superposition principle, which states that the total magnetic field at a point is the vector sum of the magnetic fields produced by individual current elements. Since the loops...
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To find the magnitude of the net magnetic field at point O due to the two identical circular loops P and Q, we can use the superposition principle, which states that the total magnetic field at a point is the vector sum of the magnetic fields produced by individual current elements.

Since the loops are identical and carry equal currents, the magnetic fields produced by each loop at point O will have the same magnitude but opposite directions due to the currents flowing in opposite directions.

Therefore, the net magnetic field at point O is the difference between the magnetic fields produced by the two loops:

Bnet=BP−BQBnet=BPBQ

Where:

  • BPBP is the magnetic field produced by loop P at point O,
  • BQBQ is the magnetic field produced by loop Q at point O.

The formula for the magnetic field at the center of a circular loop is given by:

B=μ0I2rB=2rμ0I

Where:

  • μ0μ0 is the permeability of free space (4π×10−7 T⋅m/A4π×10−7T⋅m/A),
  • II is the current flowing through the loop,
  • rr is the radius of the loop.

Since both loops have the same radius and carry equal currents, we can simplify the expression for the net magnetic field:

Bnet=μ0I2r−μ0I2rBnet=2rμ0I2rμ0I Bnet=0Bnet=0

Therefore, the magnitude of the net magnetic field at point O is zero.

 
 
 
 
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