Two charges 2 μC and −2 µC are placed at points A and B 6 cm apart. (a) Identify an equipotential surface of the system. (b) What is the direction of the electric field at every point on this surface?

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(a) The situation is represented in the given figure. An equipotential surface is the plane on which total potential is zero everywhere. This plane is normal to line AB. The plane is located at the mid-point of line AB because the magnitude of charges is the same. (b) The direction of the electric field...
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(a) The situation is represented in the given figure. An equipotential surface is the plane on which total potential is zero everywhere. This plane is normal to line AB. The plane is located at the mid-point of line AB because the magnitude of charges is the same. (b) The direction of the electric field at every point on this surface is normal to the plane in the direction of AB. read less
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Physics trainer with 4 years of experience

(A) equipotential surface will be plane perpendicular to the line joining the charge (B) direction of electric field will be long the direction of line joining of 2 μC and −2 µC from 2 μC to towards −2 µC
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Mechanical engineer with 2 years of teaching experience

(a) an equipotential surface is a plane on which potential is zero everywhere.This plane is normal to the plane in which two point charges are placed.Let normal plane be placed at C of x distance from +2μC charge.Then, potential due to 2μC + potential due to -2μC = 0Kq/x + k(-q)/(6 - x) = 0x...
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(a) an equipotential surface is a plane on which potential is zero everywhere.This plane is normal to the plane in which two point charges are placed.Let normal plane be placed at C of x distance from +2μC charge.Then, potential due to 2μC + potential due to -2μC = 0Kq/x + k(-q)/(6 - x) = 0x = 3 cmHence, the equipotential surface of the system appears at midpoint of the system of two given charges, and it is normal to the plane of charges.(B) we know, the direction of the electric field from positive to negative charge.So, the direction of the electric field at every point on the surface is normal to the plane in the direction AB. read less
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(a) As two charges are of opposite but of equal value, so equipotential surface is the perpendicular surface to the electric lines of forces that emanates from +2 μC charge and ends in -2 μC charge. (b) the electric field is perpendicular to the equipotential surface and directed from +2 μC...
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(a) As two charges are of opposite but of equal value, so equipotential surface is the perpendicular surface to the electric lines of forces that emanates from +2μC charge and ends in -2μC charge. (b) the electric field is perpendicular to the equipotential surface and directed from +2 μC to -2 μC. read less
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(a) The potential will be zero due to both charges at the equipotential surface, i.e., the plane normal to AB and passing through its midpoint has zero potential anywhere.(b) The direction of the electric field is normal to the plane in AB direction
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