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Class 12 Tuition > Learn Exercise 10 > In a Young’s double-slit experiment, the slits...
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In a Young’s double-slit experiment, the slits are separated by 0.28 mm and the screen is placed 1.4 m away. The distance between the central bright fringe and the fourth bright fringe is measured to be 1.2 cm. Determine the wavelength of light used in the experiment.

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Distance between the slits, d = 0.28 mm = 0.28 × 10−3 m Distance between the slits and the screen, D = 1.4 m Distance between the central fringe and the fourth (n = 4) fringe, u = 1.2 cm = 1.2 × 10−2 m In case of a constructive interference, we have the relation for the distance...
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Distance between the slits, d = 0.28 mm = 0.28 × 10−3 m Distance between the slits and the screen, D = 1.4 m Distance between the central fringe and the fourth (n = 4) fringe, u = 1.2 cm = 1.2 × 10−2 m In case of a constructive interference, we have the relation for the distance between the two fringes as: Where, n = Order of fringes = 4 λ = Wavelength of light used ∴ Hence, the wavelength of the light is 600 nm. read less
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