In a plane electromagnetic wave, the electric field oscillates sinusoidally at a frequency of 2.0 × 1010 Hz and amplitude 48 V m–1 .(a) What is the wavelength of the wave? (b) What is the amplitude of the oscillating magnetic field? (c) Show that the average energy density of the E field equals the average energy density of the B field. [c = 3 × 108 m s–1.]

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Frequency of the electromagnetic wave, ν = 2.0 × 1010 Hz Electric field amplitude, E0 = 48 V m−1 Speed of light, c = 3 × 108 m/s (a) Wavelength of a wave is given as: (b) Magnetic field strength is given as: (c) Energy density of the electric field is given as: And, energy density...
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Frequency of the electromagnetic wave, ν = 2.0 × 1010 Hz Electric field amplitude, E0 = 48 V m−1 Speed of light, c = 3 × 108 m/s (a) Wavelength of a wave is given as: (b) Magnetic field strength is given as: (c) Energy density of the electric field is given as: And, energy density of the magnetic field is given as: Where, ∈0 = Permittivity of free space μ0 = Permeability of free space We have the relation connecting E and B as: E = cB … (1) Where, … (2) Putting equation (2) in equation (1), we get Squaring both sides, we get read less
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