Given that the standard electrode potentials (E°) of metals are : K+/K = -2.93 V, Ag+/Ag = 0.80 V, Cu2+/Cu = 0.34 V, Mg2+/Mg = -2.37 V, Cr3+/Cr = -0.74 V, Fe2+/Fe = -0.44 V.Arrange these metals in increasing order of their reducing power.

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The reducing power of a metal is related to its ability to lose electrons and undergo oxidation. Metals with lower standard electrode potentials (E°) have a greater tendency to lose electrons and therefore are stronger reducing agents. Here are the metals arranged in increasing order of their...
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The reducing power of a metal is related to its ability to lose electrons and undergo oxidation. Metals with lower standard electrode potentials (E°) have a greater tendency to lose electrons and therefore are stronger reducing agents. Here are the metals arranged in increasing order of their reducing power based on their standard electrode potentials: K (Potassium) with E° = -2.93 V Mg (Magnesium) with E° = -2.37 V Cr (Chromium) with E° = -0.74 V Fe (Iron) with E° = -0.44 V Cu (Copper) with E° = 0.34 V Ag (Silver) with E° = 0.80 V So, the order of reducing power is: K < Mg < Cr < Fe < Cu < Ag. read less
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