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Class 12 Tuition > Learn Exercise 1 > Consider a uniform electric field E = 3 × 103...
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Consider a uniform electric field E = 3 × 103 îN/C. (a) What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane? (b) What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

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(a) Electric field intensity, = 3 × 103 î N/C Magnitude of electric field intensity, = 3 × 103 N/C Side of the square, s = 10 cm = 0.1 m Area of the square, A = s2 = 0.01 m2 The plane of the square is parallel to the y-z plane. Hence, angle between the unit vector normal to the plane...
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(a) Electric field intensity, = 3 × 103 î N/C Magnitude of electric field intensity, = 3 × 103 N/C Side of the square, s = 10 cm = 0.1 m Area of the square, A = s2 = 0.01 m2 The plane of the square is parallel to the y-z plane. Hence, angle between the unit vector normal to the plane and electric field, θ = 0° Flux (Φ) through the plane is given by the relation, Φ = = 3 × 103 × 0.01 × cos0° = 30 N m2/C (b) Plane makes an angle of 60° with the x-axis. Hence, θ = 60° Flux, Φ = = 3 × 103 × 0.01 × cos60° = 15 N m2/C read less
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