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Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol-1

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Molarity = moles of solute/litres of solution Moles= mass of solute/ molar mass of solute ∴Molarity = mass of solute/molar mass of solute x 1/litres of solution 0.375 M= mass of solute/82.0245 x 1/0.5 L Mass of solute= 15.38g Add 15.38g sodium acetate to 100ml of diluent and make up the volume...
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Molarity = moles of solute/litres of solution 

Moles= mass of solute/ molar mass of solute

∴Molarity = mass of solute/molar mass of solute x 1/litres of solution

0.375 M= mass of solute/82.0245 x 1/0.5 L

Mass of solute= 15.38g

Add 15.38g sodium acetate to 100ml of diluent and make up the volume to 500ml using the diluent 

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