A given coin has a mass of 3.0 g. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity assume that the coin is entirely made of atoms (of mass 62.92960 u).

Mass of acopper coin,m’ = 3 g Atomic mass ofatom,m= 62.92960 u The total number ofatoms in the coin Where, NA= Avogadro’s number = 6.023 × 1023atoms /g Mass number = 63 g nucleus has 29 protons and (63 − 29) 34 neutrons ∴Mass defect of this nucleus, Δm' = 29 ×mH+ 34 ×mn−m Where, Mass ofa proton,mH= 1.007825 u Mass of a neutron,mn= 1.008665 u ∴Δm' = 29 × 1.007825 + 34 × 1.008665 − 62.9296 = 0.591935u Mass defect of all the atomspresent in the coin, Δm= 0.591935 × 2.868 × 1022 = 1.69766958 × 1022u But 1 u = 931.5 MeV/c2 ∴Δm= 1.69766958 × 1022× 931.5 MeV/c2 Hence, the binding energy of the nuclei of the coin is given as: Eb=Δmc2 = 1.69766958 × 1022× 931.5 = 1.581 × 1025MeV But 1 MeV = 1.6 × 10−13J Eb=1.581 × 1025× 1.6 × 10−13 = 2.5296 × 1012J Thismuch energy is required toseparate all the neutrons and protons from the given coin. read less