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Class 12 Tuition > Learn Exercise 8.2 > Smaller area enclosed by the circle x2 + y2 = 4...
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Smaller area enclosed by the circlex2+y2= 4 and the linex+y= 2 is A. 2 (π – 2) B. π – 2 C. 2π – 1 D. 2 (π + 2)

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The smaller area enclosed by the circle, x2 + y2 = 4, and the line, x + y = 2, is represented by the shaded area ACBA as It can be observed that, Area ACBA = Area OACBO – Area (ΔOAB) Thus, the correct answer is B.
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The smaller area enclosed by the circle,x2+y2= 4, and the line,x+y= 2, is represented by the shaded area ACBA as It can be observed that, Area ACBA = Area OACBO – Area (ΔOAB) Thus, the correct answer is B. read less
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B area of circle Pi ×r^2= 4pi now area cicle divided into 4 part so area of each part is = pi now area of smaller region = area of 1 part of circle- area of triangle from by positve x,y axis and by line x+y=2 pi - 1/2*2*2= pi -2
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Total teaching experiences is 26 year's of 11 and 12

Pi _2
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