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Find the absolute maximum and minimum values of the functionfgiven by

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Now, evaluating the value of f at critical pointsand at the end points of the interval (i.e., at x = 0 and x = π), we have: Hence, the absolute maximum value of f is occurring at and the absolute minimum value of f is 1 occurring at
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Now, evaluating the value of f at critical pointsand at the end points of the interval (i.e., at x = 0 and x = π), we have: Hence, the absolute maximum value of f is occurring at and the absolute minimum value of f is 1 occurring at read less
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From first derivative test f has 2 critical points x=π/6 and x=5π/6 so find minimum and maximum value of fx So maximum vale is 5/4 and minimum value on x=0 f(0)=1
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Max value- 2 Min value--1
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Max value 2 Min value -1
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science maths tutor

f(x) max = 5/4 f(x) min= 1
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