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Differentiate the functions with respect tox.

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Let f(x)=cos(sinx), u(x)=sinx , v(t)=cost Where t=u(x)=sinx Differentiating it Since. By chain rule,
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Let f(x)=cos(sinx), u(x)=sinx , v(t)=cost Where t=u(x)=sinx Differentiating it Since.By chain rule, read less
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Tomorrow is looking great buddy

Put sin x = t and the differtiatiom of sin(x) = cos(x) so, cos(x) dx = dt dx/dt=1/cos(x) so now the question is in new form Question: cos(t) now you can solve it easily
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-Cosx*Sin(Sinx)
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Engineering graduate with little experience in teaching

-cos(X)sin(sin X)
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Maths tutor with 4 years experience

It's very simple. 1) differentiate Cos(sinx) by assuming sinx = x 2) put x=sinx back into first step 3) and then differentiate sinx 4) product of both is an answer
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It's very simple.1) differentiate Cos(sinx) by assuming sinx = x [derivative of cosx is -sinx]2) put x=sinx back into first step [1st step result = -sinx, therefore it's -sin(sinx)]3) and then differentiate sinx [derivative of sinx is cosx]4) product of both is an answer [-sin(sinx).cosx] read less
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Thus, f is a composite function of two functions. Put t = u (x) = sin x By chain rule, Alternate method
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Thus, f is a composite function of two functions. Put t = u (x) = sin x By chain rule, Alternate method read less
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