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Class 12 Tuition > Learn Exercise 6.5 > A wire of length 28 m is to be cut into two pieces....
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A wire of length 28 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a circle. What should be the length of the two pieces so that the combined area of the square and the circle is minimum?

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Let a piece of length l be cut from the given wire to make a square. Then, the other piece of wire to be made into a circle is of length (28 − l) m. Now, side of square =. Let r be the radius of the circle. Then, The combined areas of the square and the circle (A) is given by, Thus, when By second...
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Let a piece of length l be cut from the given wire to make a square. Then, the other piece of wire to be made into a circle is of length (28 − l) m. Now, side of square =. Let r be the radius of the circle. Then, The combined areas of the square and the circle (A) is given by, Thus, when By second derivative test, the area (A) is the minimum when. Hence, the combined area is the minimum when the length of the wire in making the square iscm while the length of the wire in making the circle is. read less
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B.Tech with 5 years of experience in Coaching. Specialised in Mathematics and Science subject.

(28π) ÷ (Π + 4) cm
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Related Questions

For all real values of x, the minimum value of  is

(A) 0 (B) 1

(C) 3 (D)

Let ∴By second derivative test, f is the minimum at x = 1 and the minimum value is given by . The correct answer is D.
Chiranjeevi
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