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Class 12 Tuition > Learn Additional Exercise 3 > (a) Six lead-acid type of secondary cells each of emf...
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(a) Six lead-acid type of secondary cells each of emf 2.0 V and internal resistance 0.015 Ω are joined in series to provide a supply to a resistance of 8.5 Ω. What are the current drawn from the supply and its terminal voltage?

(b) A secondary cell after long use has an emf of 1.9 V and a large internal resistance of 380 Ω. What maximum current can be drawn from the cell? Could the cell drive the starting motor of a car?

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(a) Number of secondary cells, n = 6 Emf of each secondary cell, E = 2.0 V Internal resistance of each cell, r = 0.015 Ω series resistor is connected to the combination of cells. Resistance of the resistor, R = 8.5 Ω Current drawn from the supply = I, which is given by the relation, Terminal...
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(a)Number of secondary cells,n= 6 Emf of each secondary cell,E= 2.0 V Internal resistance of each cell,r= 0.015 Ω series resistor is connected to the combination of cells. Resistance of the resistor,R= 8.5 Ω Current drawn from the supply =I, which is given by the relation, Terminal voltage,V=IR= 1.39 × 8.5 = 11.87 A Therefore, the current drawn from the supply is 1.39 A and terminal voltage is 11.87 A. (b)After a long use, emf of the secondary cell,E= 1.9 V Internal resistance of the cell,r= 380 Ω Hence, maximum current Therefore, the maximum current drawn from the cell is 0.005 A. Since a large current is required to start the motor of a car, the cell cannot be used to start a motor. read less
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