At what temperature is the root mean square speed of an atom in an argon gas cylinder equal to the rms speed of a helium gas atom at – 20 °C? (atomic mass of Ar = 39.9 u, of He = 4.0 u).

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Temperature of the helium atom, THe = –20°C= 253 K Atomic mass of argon, MAr = 39.9 u Atomic mass of helium, MHe = 4.0 u Let, (vrms)Arbe the rms speed of argon. Let (vrms)Hebe the rms speed of helium. The rms speed of argon is given by: … (i) Where, R is the universal gas constant TAr...
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Temperature of the helium atom, THe = –20°C= 253 K Atomic mass of argon, MAr = 39.9 u Atomic mass of helium, MHe = 4.0 u Let, (vrms)Arbe the rms speed of argon. Let (vrms)Hebe the rms speed of helium. The rms speed of argon is given by: … (i) Where, R is the universal gas constant TAr is temperature of argon gas The rms speed of helium is given by: … (ii) It is given that: (vrms)Ar = (vrms)He = 2523.675 = 2.52 × 103 K Therefore, the temperature of the argon atom is 2.52 × 103 K. read less
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