A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

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Mass of the car, m = 1800 kg Distance between the front and back axles, d = 1.8 m Distance between the C.G. (centre of gravity) and the back axle = 1.05 m The various forces acting on the car are shown in the following figure. Rf and Rbare the forces exerted by the level ground on the front and back...
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Mass ofthe car,m= 1800 kg Distance between the front and back axles,d= 1.8 m Distance between the C.G. (centre of gravity)and the back axle = 1.05 m The various forces acting on the car are shown in the following figure. RfandRbare the forces exerted by the level ground on the front and back wheels respectively. At translationalequilibrium: =mg = 1800 × 9.8 = 17640 N … (i) For rotational equilibrium, on taking the torque about the C.G., we have: Solving equations(i) and (ii), we get: ∴Rb= 17640 – 7350 = 10290 N Therefore, the force exerted on each front wheel, and Theforce exerted on each back wheel read less
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