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Let the amount of work done by 1 man in 1 day is w. Then the work done by (x - 3) men in (2x + 1) days=(x - 3)(2x + 1)w. And the work done by (2x + 1) men in (x + 4) days=(2x + 1)(x + 4)w. By the given condition, / = 3 : 10 Simplifying: (x - 3) / (x + 4) = 3 / 10 --> 10x - 30=3x + 12 --> 10x...

read more Let the amount of work done by 1 man in 1 day is w. Then the work done by (x - 3) men in (2x + 1) days=(x - 3)(2x + 1)w. And the work done by (2x + 1) men in (x + 4) days=(2x + 1)(x + 4)w. By the given condition, [(x - 3)(2x + 1)w] / [ (2x + 1)(x + 4)w] = 3 : 10 Simplifying: (x - 3) / (x + 4) = 3 / 10 --> 10x - 30=3x + 12 --> 10x - 3x=30 + 12 --> 7x=42 --> x = 42/7 = 6 Answer: x = 6. read less

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Always remember a formula for these type of questions where work no. of men and no. of days /working hours are given:- lhs = rhs m1 * d1* t1 / work done 1 = m2* d2* t2 / work done 2 here * = multiply and / = divide. ...

read more Always remember a formula for these type of questions where work no. of men and no. of days /working hours are given:- lhs = rhs m1 * d1* t1 / work done 1 = m2* d2* t2 / work done 2 here * = multiply and / = divide. m=men d= days As work done ratio by 1 to 2 is 3:10 just put the value (x-3)*(2x+1) /3 = (2x+1)*(x+4) /10. on solving 10x-30= 3x+12, 7x=42 Therefore x=6. read less

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Related Questions

For what value of k, do the equations 3x - y + 8 = 0 and 6x - ky = -16 represent coincident lines?

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Let a = A-2D b = A-D c = A d = A+D e = A+2D a-4b+6c-4d+e = A-2D-4(A-D)+6A-4(A+D)+A+2D = 0

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How can I get good score in class 10?

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