The sum of a number and its reciprocal is 10/3, find the number?

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Mamata Mund

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Let the number be a a+(1/a)= 10/3 => a^2+1)/a = 10/3 => 3a^2+3-10a=0 => 3a^2-10a+3=0 => 3a^2-9a-a+3=0 => 3a(a-3)-1(a-3)=0 => (3a-1)(a-3)=0 => a= 3 and a = 1/3
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