An iron pillar has some part in the form of a right circular cylinder and remaining in the form of a right circular cone. The radius of the base of each of cone and cylinder is 8 cm. The cylinderical part is 240 cm high and the conical part in 36 cm high. Find the weight of the pillar if one cu. cm of iron weighs 7.8 grams.

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Balaji Puppala

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Volume of a iron pillar=volume of a cone+ volume of a cylinder =(1/3×π×r×r×h1)+(π×r×r×h2) Given r=8, h1=36, h2=240 =π×r×r(h1/3+h2) =π×r×r(36/3+240) =π×r×r(12+240) =\7 =22×64×36=50688cm^3 Now weight of iron pillar is 50688×7.8=395366.4grams
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