A chord of a circle of radius 12 cm subtends an angle of 120° at the centre. Find the area of the corresponding segment of the circle. (Use and = 1.73)

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Let us draw a perpendicular OV on chord ST. It will bisect the chord ST. SV = VT In ΔOVS, Area of ΔOST = Area of sector OSUT = Area of segment SUT = Area of sector OSUT − Area of ΔOST = 150.72 − 62.28 = 88.44 cm2
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Let us draw a perpendicular OV on chord ST. It will bisect the chord ST. SV = VT In ΔOVS, Area of ΔOST = Area of sector OSUT = Area of segment SUT = Area of sector OSUT − Area of ΔOST = 150.72 − 62.28 = 88.44 cm2 read less
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