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When you add two numbers and the number obtained by reversing the order of its digits is 165. If the both numbers differ by three, find the number.

Tutor

Let the two numbers be "x" and "y" such that x>y Hence original digit is 10x+y, & reversed digit is 10y+x By the condition of the problem (10x+y)+ (10y+x)= 165 11x+11y=165............(1) x-y =3............(2) x+y=15............(1) divided by 11 on both sides.......(3) Adding equation (2) and (3) 2x... read more

Let the two numbers be "x" and "y" such that x>y

Hence original digit is 10x+y, & reversed digit is 10y+x

By the condition of the problem

(10x+y)+ (10y+x)= 165

11x+11y=165............(1)

x-y =3............(2)

x+y=15............(1) divided by 11 on both sides.......(3)

2x =18

x=9

y=6

therefore the two digit number is 96 and  the reverse order number is 69

so you can see that 96+69=165 and 9-6=3.......satisfies the condition of the question.

......... All the best.................

Tutor

Let x be the number and y be the another number Number obtained by reversing the order of it's digits is 651 From given data, x-y=3, x+y=561 2x=564 x=282, y=279

Math magician

one number is X ,other X +3 , so X +(x +3) = 561 or 2X = 561-3 =558 . now X =558/2 =279 ,one is 279 , other is 279 +3 =282 , answer.

Mechanical Engineer

The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of... read more

The two numbers can be any unknown variables. We will take x and y.

Reversing 165, we get 561 which means that adding them will give me 561.

Subtracting the two I will get 3. Conveting them to equations we get

x+y =561

x-y  = 3

Adding the two equations we get

2x=564

x=282

Substituting the value of x in (x-y=3)

282-y=3

Therefoe, y=279

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