When you add two numbers and the number obtained by reversing the order of its digits is 165. If the both numbers differ by three, find the number.

Asked by Last Modified  

4 Answers

Learn Mathematics +1

Follow 9
Answer

Please enter your answer

Bhaskar Raj Lal

BASK IN SUNSHINE OF INTELLECT

Let the two numbers be "x" and "y" such that x>y Hence original digit is 10x+y, & reversed digit is 10y+x By the condition of the problem (10x+y)+ (10y+x)= 165 11x+11y=165............(1) x-y =3............(2) x+y=15............(1) divided by 11 on both sides.......(3) Adding equation (2) and (3) 2x...
read more
Let the two numbers be "x" and "y" such that x>y Hence original digit is 10x+y, & reversed digit is 10y+x By the condition of the problem (10x+y)+ (10y+x)= 165 11x+11y=165............(1) x-y =3............(2) x+y=15............(1) divided by 11 on both sides.......(3) Adding equation (2) and (3) 2x =18 x=9 y=6 therefore the two digit number is 96 and the reverse order number is 69 so you can see that 96+69=165 and 9-6=3.......satisfies the condition of the question. ......... All the best................. read less
Comments
Dislike Bookmark

Tutor

Let x be the number and y be the another number Number obtained by reversing the order of it's digits is 651 From given data, x-y=3, x+y=561 2x=564 x=282, y=279
1 Comments
Dislike Bookmark

Mechanical Engineer

The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of...
read more
The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of x in (x-y=3) 282-y=3 Therefoe, y=279 read less
1 Comments
Dislike Bookmark

Math magician

one number is X ,other X +3 , so X +(x +3) = 561 or 2X = 561-3 =558 . now X =558/2 =279 ,one is 279 , other is 279 +3 =282 , answer.
1 Comments
Dislike Bookmark

View 2 more Answers

Related Questions

What's the best book on abstract algebra?
1)"Abstract Algebra" by David S. Dummit and Richard M. Foote. 2)"Contemporary Abstract Algebra" by Joseph Gallian. 3)"Algebra" by Michael Artin.
Nazia
0 0
8
What I should do study for coming in merit list of 10th board exam?
Determination and regularity are key points. Make plan, make small achievable goal and do it for that. Make schedule of daily and must follow with giving them high preference.
Hole
What is the formula for geometric mean?
if a,b,c are in gp then GM b=√(a*c)
Brunda
How much monthly fees for Maths for class 10 in Delhi or NCR?
350-400/ hour.
Vishal Ranjan
What is the difference between Arithmetic mean and Geometric mean?
If x, y are two no then AM=(x+y)/2 and GM = (xy)^(1/2).
Ambar
0 0
8

Now ask question in any of the 1000+ Categories, and get Answers from Tutors and Trainers on UrbanPro.com

Ask a Question

Related Lessons

Class 10 Algebra
1. Choose the correct option: If a + b + c = 0 then a3 + b3 + c3 is equal to_____A) 0B) abcC) 3abcD) 2abc 2. The 17th term of an AP is 17 and its 14th term is 29. the common difference of the AP isA)...
B

Binu T.

0 0
0
Class-10-AP-1-PYqs-2023

Ashish Bhatia

0 0
0
Class-10 L-5 Arithmetic Progressions Ex-5.3 Q3 (x)

Ashish Bhatia

0 0
0
Class-10 L-8 Introduction to Trigonometry Ex-8.3 Q3 (ii)

Ashish Bhatia

0 0
0
Class-10 L-5 Arithmetic Progressions Ex-5.2 Q1 (v)

Ashish Bhatia

0 0
0

Recommended Articles

Quest Academy - Institute of the month

Quest Academy is a professional Bangalore based NEET and JEE (Main + Advanced) training institute. The academy was incorporated in 2015 to cater to the needs of students, who aim to crack competitive exams by connecting with the best brains around. The institute helps students enhance their skills and capabilities through...

Read full article >

Meet Raghunandan.G.H, a B. Tech Tutor from...

Raghunandan is a passionate teacher with a decade of teaching experience. Being a skilled trainer with extensive knowledge, he provides high-quality BTech, Class 10 and Class 12 tuition classes. His methods of teaching with real-time examples makes difficult topics simple to understand. He explains every concept in-detail...

Read full article >

Meet Mohammad Wazid, a skilled trainer for...

Mohammad Wazid is a certified professional tutor for class 11 students. He has 6 years of teaching experience which he couples with an energetic attitude and a vision of making any subject easy for the students. Over the years he has developed skills with a capability of understanding the requirements of the students. This...

Read full article >

Meet Swati, a Hindi Tutor from Bangalore

Swati is a renowned Hindi tutor with 7 years of experience in teaching. She conducts classes for various students ranging from class 6- class 12 and also BA students. Having pursued her education at Madras University where she did her Masters in Hindi, Swati knows her way around students. She believes that each student...

Read full article >

Find Class 10 Tuition near you
Class 10 Tuition in Delhi
Class 10 Tuition in Bangalore
Class 10 Tuition in Hyderabad
Class 10 Tuition in Kolkata
Class 10 Tuition in Chennai
Class 10 Tuition in Mumbai
Class 10 Tuition in Pune
Class 10 Tuition in Noida
Class 10 Tuition in Lucknow
Class 10 Tuition in Gurgaon
Online Tuition Class 10

Looking for Class 10 Tuition ?

Learn from the Best Tutors on UrbanPro

Are you a Tutor or Training Institute?

Join UrbanPro Today to find students near you