When you add two numbers and the number obtained by reversing the order of its digits is 165. If the both numbers differ by three, find the number.

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Bhaskar Raj Lal

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Let the two numbers be "x" and "y" such that x>y Hence original digit is 10x+y, & reversed digit is 10y+x By the condition of the problem (10x+y)+ (10y+x)= 165 11x+11y=165............(1) x-y =3............(2) x+y=15............(1) divided by 11 on both sides.......(3) Adding equation (2) and (3) 2x...
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Let the two numbers be "x" and "y" such that x>y Hence original digit is 10x+y, & reversed digit is 10y+x By the condition of the problem (10x+y)+ (10y+x)= 165 11x+11y=165............(1) x-y =3............(2) x+y=15............(1) divided by 11 on both sides.......(3) Adding equation (2) and (3) 2x =18 x=9 y=6 therefore the two digit number is 96 and the reverse order number is 69 so you can see that 96+69=165 and 9-6=3.......satisfies the condition of the question. ......... All the best................. read less
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Let x be the number and y be the another number Number obtained by reversing the order of it's digits is 651 From given data, x-y=3, x+y=561 2x=564 x=282, y=279
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Mechanical Engineer

The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of...
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The two numbers can be any unknown variables. We will take x and y. Reversing 165, we get 561 which means that adding them will give me 561. Subtracting the two I will get 3. Conveting them to equations we get x+y =561 x-y = 3 Adding the two equations we get 2x=564 x=282 Substituting the value of x in (x-y=3) 282-y=3 Therefoe, y=279 read less
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Math magician

one number is X ,other X +3 , so X +(x +3) = 561 or 2X = 561-3 =558 . now X =558/2 =279 ,one is 279 , other is 279 +3 =282 , answer.
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